Chapter 4, Problem 79E

(a)

Interpretation Introduction

Interpretation: The volume of $\text{HCl}$ required to precipitate silver $\left({\text{Ag}}^{\text{+}}\right)$ ions from $\text{0}\text{.200}\text{M}$ of $\text{15}\text{.0}\text{mL}$ of ${\text{AgNO}}_3$ solution.

Concept introduction:
Volume of $\text{HCl}$ is calculated by the ratio of number of moles to the molarity.  $\text{Volume}\text{of}\text{HCl=}\frac{\text{Moles of}\text{HCl}}{\text{Molarity}}$

(b)

Interpretation Introduction

Interpretation: The mass of $\text{KCl}$ required to precipitate silver $\left({\text{Ag}}^{\text{+}}\right)$ ions from $\text{0}\text{.200}\text{M}$ of $\text{15}\text{.0}\text{mL}$ of ${\text{AgNO}}_3$ solution.

Concept introduction:
Mass of $\text{KCl}$ is calculated by the product of molar mass of $\text{KCl}$ and number of moles of $\text{KCl}$ .
$\text{Mass}\text{of}\text{KCl}=\text{Moles}\text{of}\text{KCl}\times \text{Molar}\text{mass}\text{of}\text{KCl}$

(d)

Interpretation Introduction

Interpretation: The cost effective procedure among the given procedures.

Concept introduction:

The procedure which gives a good result without costing a lot of money is said to be cost effective procedure.