Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 4, Problem 6P
Neptune orbits the Sun with a period of 164.8 years. What is its average distance from the Sun?
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Chapter 4 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 4 - Why did Greek astronomers conclude that the...Ch. 4 - Why did classical astronomers conclude that Earth...Ch. 4 - How did the Ptolemaic model explain retrograde...Ch. 4 - In what ways were the models of Ptolemy and...Ch. 4 - Why did the Copernican hypothesis win gradual...Ch. 4 - Why is it difficult for scientists to replace an...Ch. 4 - Why did Tycho Brahe expect the new star of 1572 to...Ch. 4 - How was Tycho’s model of the Universe similar to...Ch. 4 - Explain how Kapler’s lows contradict uniform...Ch. 4 - What is the difference between a hypothesis ,...
Ch. 4 - How did The Alfonsine Tables, The Prutenic Tables,...Ch. 4 - Review Galileo’s telescopic discoveries and...Ch. 4 - Galileo was condemned by the Inquisition, but...Ch. 4 - How do Newton’s laws lead you to conclude that...Ch. 4 - Explain why you might describe the orbital motion...Ch. 4 - Prob. 16RQCh. 4 - How Do We know? How would you respond to someone...Ch. 4 - Prob. 18RQCh. 4 - How Do We Know? Why is it important that a...Ch. 4 - Science historian Thomas Kuhn has said that De...Ch. 4 - Many historians suspect that Galileo offended Pope...Ch. 4 - Prob. 3DQCh. 4 - If you lived on Mars, which planets would describe...Ch. 4 - Galileo’s telescope showed him that Venus has a...Ch. 4 - Galileo’s telescopes were not of high quality by...Ch. 4 - If a planet had an average distance from the Sun...Ch. 4 - If a space probe were sent into an orbit around...Ch. 4 - Neptune orbits the Sun with a period of 164.8...Ch. 4 - Venus’s average distance from the Sun is 0.72 AU...Ch. 4 - The circular velocity of Earth around the Sun is...Ch. 4 - What is the orbital velocity of an Earth satellite...Ch. 4 - Prob. 1LTLCh. 4 - Prob. 2LTLCh. 4 - Why is it a little bit misleading to say that this...Ch. 4 - Prob. 4LTLCh. 4 - Mercury’s orbit hardly deviates from a circle, but...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Estimate the length of period of Neptune assuming that the length of the semimajor axis of the ellipse is a = 449.51 x 101º m. For Earth, a = 15.0 × 1010 m. (Use decimal notation. Give your answer to two decimal places.)arrow_forwardNeptune circles the Sun at a distance of 4.30 x 10^12 m once every 164 yeras. Saturn circles the Sun at a distance 1.43 x 10^12 m. Orbital period of Saturn?arrow_forwardThe asteroid Ceres has a mass of 9.39 ✕ 1020 kg and an average radius of about 473 km (4.73 ✕ 102 km). What is its escape velocity (in m/s)? (Hints: Use the formula for escape velocity)arrow_forward
- The chart shows the length of time for each planet, in Earth days, to make one complete revolution around the Sun. Orbital Period of Planets iY the Solar System Orbital Period (Earth days) 88 225 365 687 4333 10 759 30 685 60 189 Planet Mercury Venus Earth Mars Jupiter Satum Uranus Neptune Source: NASA Use the data table above to compare the length of a year on Mars and Neptune. (HS-ESS1-4) a. One year on Neptune is almost 100 times longer than a year on Mars. b. One year on these two planets is nearly equal. c. One year on Mars is almost 100 times longer than a year on Neptune. d. One year these two planets is roughly equal to a year on Earth. Use the data table above to determine which of the following statements is TRUE. (HS-ESS1-4) a. There is no relationship between a planet's distance from the Sun and its length of year. b. The closer a planet is to the Sun, the longer the planet's year. c. One year on all planets is about 365 days long. d. The farther away a planet is from the…arrow_forwardTwo exoplanets, UCF1.01 and UCF1.02 are found revolving around the same star. The period of planet UCF1.01 is 4.8 days, and that of planet UCF1.02 is 5.2 days. If the average distance of planet A to the sun is 2,885.4 km, what is the average distance of planet B to the sun km? Please keep four digits after decimal points.arrow_forwardOrbital Radius and orbital period data for the four biggest moons of Jupiter are listed in the table below. The mass of the planet Jupiter is 1.9 × 1027 kg. Jupiter's Moon Period (s) Radius (m) T2/r3 Io 1.53×105 4.2×108 ? Europa 3.07×105 6.7×108 ? Ganymede 6.18×105 1.1×109 ? Callisto 1.44×106 1.9×109 ? What pattern do you observe in the last column of data? Which law of Kepler's does this seem to support?arrow_forward
- It takes Mercury about 88 days to revolve once around the sun. It takes Jupiter about 11.86 years to revolve once around the sun. How many revolutions does Mercury make around the sun in the time it takes Jupiter to revolve once around the sun? Use the conversion factor of 1 year = 365 days. Round your answer to the nearest tenth.arrow_forwardSaturn's mass is M= 5.69 x 1026 kg and its radius R=60,300 km. If a moon orbits Saturn at a distance equal to 5 times its planetary radius, what is its period of orbit? (Hint, use Newton's version of Kepler's 3rd law, and you can neglect the mass of the moon) Express your answer in days to three significant figures.arrow_forwardIo orbits Jupiter at an average distance of 4.22 105 km with an orbital period of 0.00485 yr. The Moon, which is one of the satellites of the Earth, orbits its parent at an average distance of 3.84 105 km with an orbital period of 0.07481 yr. (a) Use the above information to find the orbital speeds of Io around Jupiter and of the Moon around the Earth. vMoon = m/s vIo = m/s (b) What is the expression for the mass M of the parent in terms of the orbital speed v of the satellite, the orbital radius R of the satellite and the gravitational constant G? (Do not substitute numerical values; use variables only.)M = (c) Now use your answers from parts (a) and (b) to find the ratio of the mass of the Earth to that of Jupiter. ME MJarrow_forward
- Saturn has an orbital period of 29.6 years. Explain how to calculate the average distance from the saturn to the sunarrow_forward(to two decimal places): (what is ‘h’?) Eccentricity of earth orbit is 0.0167 µ(sun) = 1.32712E+11 km^3/s^ semimajor axis of Earth orbit = 1.49598E+08 need to figure out what ‘h’ is. a) Calculate the speed of the earth around the sun at aphelion? (29.29 KM/S) b) At perihelion? (30.29 KM/S)arrow_forwardThe distance from the sun to saturn is approximatelyarrow_forward
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