Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 4, Problem 3LTL
Why is it a little bit misleading to say that this astronaut is weightless (see Figure UN 4-7)?
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Chapter 4 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 4 - Why did Greek astronomers conclude that the...Ch. 4 - Why did classical astronomers conclude that Earth...Ch. 4 - How did the Ptolemaic model explain retrograde...Ch. 4 - In what ways were the models of Ptolemy and...Ch. 4 - Why did the Copernican hypothesis win gradual...Ch. 4 - Why is it difficult for scientists to replace an...Ch. 4 - Why did Tycho Brahe expect the new star of 1572 to...Ch. 4 - How was Tycho’s model of the Universe similar to...Ch. 4 - Explain how Kapler’s lows contradict uniform...Ch. 4 - What is the difference between a hypothesis ,...
Ch. 4 - How did The Alfonsine Tables, The Prutenic Tables,...Ch. 4 - Review Galileo’s telescopic discoveries and...Ch. 4 - Galileo was condemned by the Inquisition, but...Ch. 4 - How do Newton’s laws lead you to conclude that...Ch. 4 - Explain why you might describe the orbital motion...Ch. 4 - Prob. 16RQCh. 4 - How Do We know? How would you respond to someone...Ch. 4 - Prob. 18RQCh. 4 - How Do We Know? Why is it important that a...Ch. 4 - Science historian Thomas Kuhn has said that De...Ch. 4 - Many historians suspect that Galileo offended Pope...Ch. 4 - Prob. 3DQCh. 4 - If you lived on Mars, which planets would describe...Ch. 4 - Galileo’s telescope showed him that Venus has a...Ch. 4 - Galileo’s telescopes were not of high quality by...Ch. 4 - If a planet had an average distance from the Sun...Ch. 4 - If a space probe were sent into an orbit around...Ch. 4 - Neptune orbits the Sun with a period of 164.8...Ch. 4 - Venus’s average distance from the Sun is 0.72 AU...Ch. 4 - The circular velocity of Earth around the Sun is...Ch. 4 - What is the orbital velocity of an Earth satellite...Ch. 4 - Prob. 1LTLCh. 4 - Prob. 2LTLCh. 4 - Why is it a little bit misleading to say that this...Ch. 4 - Prob. 4LTLCh. 4 - Mercury’s orbit hardly deviates from a circle, but...
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- Please complete full question. The answer is of no use without it.arrow_forwardWhen the Earth passes directly between the Sun and Mars, the Earth and Mars are closest to each other. If Mars is 1.52 AU from the Sun and there are 1.5 x 108 km in 1 AU, how many times will the width of the U.S. (2,530 miles) fit end-to-end between Mars and Earth? Planets and Sun not drawn to scale. Mars Earth Sun Part 1 of 4 Mars is 1.52 AU from the Sun. How many times further away from the Sun is Mars than the Earth? (The distances in AU are relative to the distance between the Sun and the Earth, so however many AU a planet is away from the Sun is how many times farther it is from Sun than Earth.) 1.52✔ 1.52 times further awayarrow_forwardImagine that it were possible to construct a combination spacecraft and time machine, for the purpose of visiting various parts of the solar system in the distant past and future. If you and a friend had such a thing, and your friend said "let's go stand on the surface of the Earth during the accretion phase of its early history", why might that not be a good idea? Group of answer choices The Earth would be so barren and inactive, with virtually no atmosphere and nothing happening on its surface, that you wouldn't find any resources to survive. This phase happened shortly after the Moon formed, so the Earth's surface might still be hot after the Moon-forming impact. During the Earth's accretion phase, there were many hazardous life forms on its surface, such as dinosaurs and other potentially predatory animals. Many asteroids and meteoroids would be impacting the surface of the Earth, as they built up the planet. PreviousNextarrow_forward
- Pl:5: this was all information that was given to me. If need i would need to look it up online.arrow_forwardCalculate the escape velocity in km/s to 2 decimal places on Mars given; • Mass of Mars = 6.24 * 1023 kg -Mm624103. • Diameter of Mars = 6794 km %3|arrow_forwardhelp me answer the question for Carrow_forward
- Use a distance of R = 1.48x10^11 meters for the distance between the earth and the sun. Use a mass of 1.99x10^30 kg to be 1 solar mass. For each of the different sun masses (as values of solar mass, aka 0.5 solar masses = 1x10^30 kg), as outlined in the lecture, calculate the period of the earth's orbit in days using Kepler's law for circular orbits (I double-checked it with these values and it works) and also calculate the corresponding orbital velocity of the earth. Questions: 1.) Using these values, and 6x10^24 kg for the mass of the earth, what is the strength of the gravitational force between the earth and the sun? 2.) If the earth were twice as far from the sun, what would be its period of orbit? 3.) Mars orbits the sun at a distance of 2.18x10^11 meters. How long is a Martian year, using Kepler's law for circular orbits?arrow_forwardSince 1995, hundreds of extrasolar planets have been discovered. There is the exciting possibility that there is life on one or more of these planets. To support life similar to that on the Earth, the planet must have liquid water. For an Earth-like planet orbiting a star like the Sun, this requirement means that the planet must be within a habitable zone of 0.9 AU to 1.4 AU from the star. The semimajor axis of an extrasolar planet is inferred from its period. What range in periods corresponds to the habitable zone for an Earth-like Planet orbiting a Sun-like star?arrow_forwardBased Figure 4-13c, do planets with larger a take longer, shorter, or the same time to orbit the Sun?arrow_forward
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