The more stable compound from given compounds cis-1,2-dimethylcyclopropane , trans-1,2-dimethylcyclopropane has to be identified. Concept introduction: Cyclopropane compounds are the smallest cyclic compounds. The atoms are very closely located in cyclopropane compounds. Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane. The increasing cost energy order of eclipsed atoms/groups is, H/H ( 4 kJ/mol ) < H/CH 3 ( 6 kJ/mol ) < CH 3 /CH 3 ( 11 kJ/mol )

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Answer 1

Question

Chapter 4, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

The more stable compound from given compounds cis-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane has to be identified.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

(b)

Interpretation Introduction

Interpretation:

The energy difference between the two compounds has to be predicted.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

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Answer 2

Question

Chapter 4, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

The more stable compound from given compounds cis-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane has to be identified.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

(b)

Interpretation Introduction

Interpretation:

The energy difference between the two compounds has to be predicted.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

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Answer 3

Question

Chapter 4, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

The more stable compound from given compounds cis-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane has to be identified.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

(b)

Interpretation Introduction

Interpretation:

The energy difference between the two compounds has to be predicted.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

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Answer 4

Question

Chapter 4, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

The more stable compound from given compounds cis-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane has to be identified.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

(b)

Interpretation Introduction

Interpretation:

The energy difference between the two compounds has to be predicted.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

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Answer 5

Chapter 4, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

The more stable compound from given compounds cis-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane has to be identified.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

(b)

Interpretation Introduction

Interpretation:

The energy difference between the two compounds has to be predicted.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

Answer 6

Chapter 4, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

The more stable compound from given compounds cis-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane has to be identified.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

Answer 7

Chapter 4, Problem 67IP

(a)

Interpretation Introduction

Interpretation:

The more stable compound from given compounds cis-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane has to be identified.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

Answer 8

(b)

Interpretation Introduction

Interpretation:

The energy difference between the two compounds has to be predicted.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

Answer 9

(b)

Interpretation Introduction

Interpretation:

The energy difference between the two compounds has to be predicted.

Concept introduction:

Cyclopropane compounds are the smallest cyclic compounds.

The atoms are very closely located in cyclopropane compounds.

Every atoms/groups attached to the carbon atoms of cyclopropane are eclipsing in below the plane and above the plane.

The increasing cost energy order of eclipsed atoms/groups is,

H/H (4 kJ/mol) < H/CH3(6 kJ/mol) < CH3/CH3(11 kJ/mol)

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 4.2 - Prob. 1LTS Ch. 4.2 - Prob. 1PTS Ch. 4.2 - Prob. 2ATS Ch. 4.2 - Prob. 3ATS Ch. 4.2 - Prob. 4ATS Ch. 4.2 - Prob. 2LTS Ch. 4.2 - Prob. 5PTS Ch. 4.2 - Prob. 6ATS Ch. 4.2 - Prob. 3LTS Ch. 4.2 - Prob. 7PTS

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Chapter 4 Solutions