EBK COMPUTER SCIENCE ILLUMINATED
EBK COMPUTER SCIENCE ILLUMINATED
7th Edition
ISBN: 9781284174755
Author: Dale
Publisher: JONES+B CO
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Chapter 4, Problem 60E
Program Plan Intro

Circuit:

  • The circuit is known as the combination of gates that is used to achieve a difficult logical operation.
  • It has two general categories; they are:
    • Combinational circuit
    • Sequential circuit

Expert Solution & Answer
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Explanation of Solution

Given circuit diagram:

EBK COMPUTER SCIENCE ILLUMINATED, Chapter 4, Problem 60E

Behavior of the circuit:

  • From the circuit diagram:
    • First, the input A is passed to NOT gate to perform the inverse of the A and produces the output as A¯.
    • Next, the input A and input B is passed in the AND gate to perform the product of A and B, to produce the output as AB.
    • Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
      • Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
      • That is, “A¯” and “AB” are passed as the input for XOR gate and produce as the output A¯(AB).

Truth table for the given circuit diagram:

Step 1:

  • The inputs are A and B for the above circuit diagram:
ABA¯ABA¯(AB)
00   
01   
10   
11   

Step 2:

  • When the inputs are A as 0 and B as 0:
ABA¯ABA¯(AB)
00101
01   
10   
11   
  • First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 10=1 .
  • Next, the input A as 0 and input B as 0 is passed to the AND gate to perform the product of A and B and produce the output as  s.
  • Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
    • Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
    • That is, “1” and “0” are passed as inputs to XOR gate and produces output as  10=1.

Step 3:

  • When the inputs are A as 0 and B as 1:
ABA¯ABA¯(AB)
00101
01101
10   
11   
  • First, the input A as 0 is passed to NOT gate to perform the inverse of the A and produces the output as 0¯=1.
  • Next, the input A as 0 and input B as 1 is passed to the AND gate to perform the product of the A and B and produce the output as  01= .
  • Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
    • Note: when both the inputs are the same, then the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
    • That is, “1” and “0” are passed as input for XOR gate and produce output as 10=1.

Step 4:

  • When the inputs are A as 1 and B as 0:
ABA¯ABA¯(AB)
00101
01101
10000
11   
  • First, the input A as 1 is passed to NOT gate to perform the inverse of A and produces the output as  1 ¯=0 .
  • Next, the input A as 1 and input B as 0 is passed in the AND gate to perform the product of the A and B and produce the output as 10=0.
  • Finally, the output of NOT gate and the output of AND gate is passed as the input to XOR gate.
    • Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
    • That is, “0” and “0” are passed as input for XOR gate and produce as the output 00=0.

Step 5:

  • When the inputs are A as 1 and B as 1:
ABA¯ABA¯(AB)
00101
01101
10000
11011
  • First, the input A as 1 is passed to NOT gate to perform the inverse of the A and produces the output as  1 ¯=0.
  • Next, the input A and input B as 1 is passed in the AND gate to perform the product of the A and B and produce the output as 11=1.
  • Finally, the output of NOT gate and the output of AND gate is passed as the input of XOR gate.
    • Note: when both the inputs of XOR gate are the same, the output of XOR gate is 0. Otherwise, the output of XOR gate is 1.
    • That is, “0” and “1” are passed as input for XOR gate and produce as the output 01=1.

Final truth table:

Therefore, truth table of the given circuit diagram is:

ABA¯ABA¯(AB)
00101
01101
10000
11011

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