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MindTap for Herman's Understanding Motor Controls, 4th Edition [Instant Access], 2 terms
4th Edition
ISBN: 9781337798754
Author: Herman; Stephen L.
Publisher: Cengage Learning US
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Chapter 4, Problem 5RQ
Why is it necessary to permit a solder melting type of overload relay to cool for two to three minutes after it has tripped?
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Select the valid option from the list below.
E
F
G
20 kN
RAX = ?? KN
30°
30°
30°
30°
30°
30°
A
B
D
RAY = ?? KN
A The solution to the problem is found to be -10.0 kN.
B. The solution to the problem is found to be -20.0 KN.
○ C. The solution to the problem is found to be +11.5 kN.
D. The solution to the problem is found to be +23.1 kN.
E. No Valid Answer
Roy = ?? KN
Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful!
Please do not copy other's work,i will be very very grateful!!
Answer by selecting the correct options from the following multichoice selection.
ப
4m
B
A
C
D
3m
3 m
Figure Q17
FL
12 kN
E
16 KN
A. We should resolve forces in the horizontal direction to easily identify the internal force DF.
B. The solution to the problem is found to be -16 kN (C).
C. We should resolve forces in the vertical direction to first identify the internal force DF.
D. We should use Method of Joints at node F to find the internal force in member DF.
E. We should Method of Sections by cutting through members DF, DE and CE.
F. The starting point to solve this problem is to find all reactions at nodes A and B as they will be required for DF calculations.
G. The solution to the problem is found to be 16 kN (T).
H. The most appropriate method to find DF use is Method of Joints.
I. The most appropriate method to use is Method of Sections.
J. A good starting point to solve this problem is to find the horizontal reaction at node B but this is not required to the internal force
Chapter 4 Solutions
MindTap for Herman's Understanding Motor Controls, 4th Edition [Instant Access], 2 terms
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- H 2 kN K 2 kN M N www RAY RAX A G B C D E F 3 m ↑ RGY 4m Fill in the multiple blanks. Figure Q19 Finding the vertical reactions is the starting point which can be done by taking moments at A and G but since this is symmetrical loading case the vertical reactions can simply be calculated by halving the total loading 4 kN. Ideally, we can solve the problem using the Method of cutting through the members JK, DJ and It would be sensible to select the left-hand side of the diagram as there are less full members and only one force from the reaction at node A. This will expose the internal forces which can be labelled with the names of the members themselves. Since we are required to find JK, examining the framework shows it is not a straight-forward matter, and we will require finding all three unknown internal forces. The easiest internal force to find is Next, we can take moments at node , as we can resolve forces in the vertical direction. in order to find the internal force JK and find…arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward
- Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward(19) Figure Q19 shows a framework consisting of horizontal members 3 m long and vertical members 4 m long. The framework is loaded at joints J and L with downward load forces of 2 kN. The applied forces cause a vertical reaction forces at A and G and no horizontal reaction force. You are asked to find the internal force in member JK - what would be your approach to solve this problem? Explain your solution process and some of your results by filling in the blanks below. 2 kN 2 kN H RAY RAX A K M N B C D E F 3 m 1 RGY 4m Fill in the multiple blanks. Figure Q19 Finding the vertical reactions is the starting point which can be done by taking moments at A and G but since this is symmetrical loading case the vertical reactions can simply be calculated by halving the total loading 4 kN. Ideally, we can solve the problem using the Method of cutting through the members JK, DJ and It would be sensible to select the left-hand side of the diagram as there are less full members and only one force…arrow_forward4m A 72 kN C E B D F 144 kN 3 m 3 m 3 m Figure Q16 Fill in the multiple blanks below. To find the reactions the starting point is to take moments at a suitable node location. Since node unknowns it is the ideal location to first take moments. By taking moments in a clockwise orientation we find a moment of there is an additional moment of 288 kNm from the load at C. From combining all moments together, we can then find the vertical reaction at F which is RFy= place. For best practice, it is a good approach to take moments at has two kNm due to the force load at node B and KN to 1 decimal in order to the find the vertical reaction RAY- Finally, we can sum forces in the horizontal direction to find the reaction RAX = -72 kN, assuming the reaction at A acts left-to-right. After which we can then sum forces in the vertical direction to verify the sum of RAY plus Rgy is the same as the total downwards force which should be KN.arrow_forward
- Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward10 kN A B 1m RBY 20 kN/m 30 kN с D E 1m 1m 1m Find the vertical reaction Rgy at B Figure Q18 Find the vertical reaction REY at E Verify the reactions Rgy and REY are valid ✓ Find the Bending Moment value at C You could find the Bending Moment value at B شه A. by finding the area on the Shear Force graph left of B (treating areas underneath the x-axis as negative). B. by taking moments at B. C. by taking moments of all forces left of C. D. by taking moments at E. E. by summing all forces in a vertical direction.arrow_forwardPlease do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful! Please do not copy other's work,i will be very very grateful!!arrow_forward
- (10) A regular cross-section XXY mm beam, where X=84 m and Y=77 m and 1800 mm long, is loaded from above in the middle with a load of Z=2 kN causing a compressive Bending Stress at the top of the beam and tensile Bending Stress at the bottom of the beam. The beam in addition experiences a tensile end loading in order to reduce the compressive stress in the beam to a near zero value. The configuration of the beam is illustrated in Figure Q10. Calculate the end loading force required in order to reduce total compressive stress experienced in the beam to be near zero? State your answer to the nearest 1 decimal place in terms of kilo-Newtons. X mm Y mm ? KN Z KN Figure Q10 1800 mm ? KNarrow_forward(13) A cylindrical beam of length 2 m and diameter of 120 mm, is arranged with a loading in the middle and two supports either end, as shown in Figure Q13. Given the shaft is made of metal which has a tensile strength of 350 MPa. Select the safest Factor of Safety (FOS) to 1 decimal place that the design engineer should work to. 100 kN ○ A. 1.2 ○ B. No Valid Answer ○ c. 1.1 O D.3.7 E. 0.8 2 m Figure Q13 120 mmarrow_forwardThe pin-connected assembly consists of bronze rods (1) and (2) and steel rod (3). The bronze rods each have a diameter of 12mm and an elastic modulus of E=120GPa. The steel rod has a diameter of 18mm and an elastic modulus of E 210 GPa. Assume a= 2.0 m, b=1.5 m, and c = 2.0 m. What is the magnitude of load P that is necessary to displace point A 5mm to the left? a 5.52kN 17.05kN 5.05kN d 6.75kN Right answer need, no chatgpt,only handwrittenarrow_forward
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