Bundle: Understanding Motor Controls, 4th + Mindtap Electrical, 2 Terms (12 Months) Printed Access Card
4th Edition
ISBN: 9780357097755
Author: Stephen L. Herman
Publisher: Cengage Learning
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Chapter 4, Problem 5RQ
Why is it necessary to permit a solder melting type of overload relay to cool for two to three minutes after it has tripped?
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d₁
=
=
Two solid cylindrical road AB and
BC are welded together at B and
loaded as shown. Knowing that
30mm (for AB) and d₂
50mm (for BC), find the average
normal stress in each road and the
total deformation of road AB and
BC. E=220GPa
H.W 5.3
60kN
A
For the previous example calculate the
value of force P so that the point A will not
move, and what is the total length of road
AB at that force?
P◄
A
125kN
125kN
0.9m
125kN
125kN
0.9m
B
B
1.3m
1.3m
Class:
B
Calculate the load that will make point A move to the left by 6mm, E-228GPa
The cross sections of the rods are as shown in fig. below.
183
P-
Solution
1.418mm
200mm
80mm
3P-
18.3
A
080mm
B
200mm
3P-
0.9m
إعدادات العرض
1.3m
4.061mm
H.W6
Determine the largest weight
W that can be supported by
two wires shown in Fig. P109.
The stress in either wire is not
to exceed 30 ksi. The cross-
sectional areas of wires AB
and AC are 0.4 in2 and 0.5
in2, respectively.
50°
30°
W
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Bundle: Understanding Motor Controls, 4th + Mindtap Electrical, 2 Terms (12 Months) Printed Access Card
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- 20 3. 2-233 2520 Тр Gears 1079 A pair of helical gears consist of a 20 teeth pinion meshing with a 100 teeth gear. The pinion rotates at Ta 720 r.p.m. The normal pressure angle is 20° while the helix angle is 25°. The face width is 40 mm and the normal module is 4 mm. The pinion as well as gear are made of steel having ultimate strength of 600 MPa and heat treated to a surface hardness of 300 B.H.N. The service factor and factor of safety are 1.5 and 2 respectively. Assume that the velocity factor accounts for the dynamic load and calculate the power transmitting capacity of the gears. [Ans. 8.6 kWarrow_forward4. A single stage helical gear reducer is to receive power from a 1440 r.p.m., 25 kW induction motor. The gear tooth profile is involute full depth with 20° normal pressure angle. The helix angle is 23°, number of teeth on pinion is 20 and the gear ratio is 3. Both the gears are made of steel with allowable beam stress of 90 MPa and hardness 250 B.H.N. (a) Design the gears for 20% overload carrying capacity from standpoint of bending strength and wear, (b) If the incremental dynamic load of 8 kN is estimated in tangential plane, what will be the safe power transmitted by the pair at the same speed?arrow_forwardDetermine the stress in each section of the bar shown in Fig. when subjected to an axial tensile load shown in Fig. The central section is 30 mm hollow square cross- section; the other portions are of circular section, their diameters being indicated What will be the total deformation of the bar? For the bar material E = 210GPa. 20mi О 30mm 30mmm 2.6 15mm 30kN 1 2 10kN - 20kN 3 -329 91mm 100mm 371mmarrow_forward
- Calculate the load that will make point A move to the left by 6mm, E=228GPa. The diameters of the rods are as shown in fig. below. 2P- PA 80mm B 200mm 2P 0.9m 1.3m.arrow_forwardIf the rods are made from a square section with the dimension as shown. Calculate the load that will make point A move to the left by 6mm, E=228GPa. 2P- P A 80mm B 200mm 2P 0.9m 1.3marrow_forward3. 9. 10. The centrifugal tension in belts (a) increases power transmitted (b) decreases power transmitted (c) have no effect on the power transmitted (d) increases power transmitted upto a certain speed and then decreases When the belt is stationary, it is subjected to some tension, known as initial tension. The value of this tension is equal to the (a) tension in the tight side of the belt (b) tension in the slack side of the belt (c) sum of the tensions in the tight side and slack side of the belt (d) average tension of the tight side and slack side of the belt The relation between the pitch of the chain (p) and pitch circle diameter of the sprocket (d) is given by 60° (a) p=d sin (c) p=d sin (120° T where T Number of teeth on the sprocket. 90° (b) p=d sin T 180° (d) p=d sin Tarrow_forward
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