Chapter 4, Problem 54QRT

(a)

Interpretation Introduction

Interpretation:

For formation of $97.8\text{ g }KCl\left(s\right)$ the q value at constant pressure has to be calculated.

Concept Introduction:

Enthalpy is the amount energy absorbed or released in a process. Under constant pressure conditions the enthalpy change will be equal to molar q.

    ${\text{q = nΔ}}_{\text{r}}{\text{H}}^{\text{o}}$

Here, q is amount of heat; n is no of moles and ${\text{Δ}}_{\text{r}}{\text{H}}^{\text{o}}$ is enthalpy change.

Number of moles (n) of substance can be determined by using the given formula,

  $n\text{ = }\frac{m}{M}$

Here, m is the mass of the substance and M is the molar mass.

(b)

Interpretation Introduction

Interpretation:

For formation of $24.8mol{\text{ O}}_{\text{2}}\left(g\right)$ the q value at constant pressure has to be calculated.

Concept Introduction:

Refer part (a).

(c)

Interpretation Introduction

Interpretation:

For decomposition of $35.2g{\text{ KClO}}_3\left(s\right)$ the q value at constant pressure has to be calculated.

Concept Introduction:

Refer part (a).