EBK ACTIVITIES MANUAL FOR PROGRAMMABLE
5th Edition
ISBN: 8220102795983
Author: Petruzella
Publisher: YUZU
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Expert Solution & Answer
Chapter 4, Problem 4P
Explanation of Solution
a.
Data stored in the destination address of AND operation:
- In AND operation, the output is always HIGH when all the inputs are HIGH and the output is LOW when any of the inputs are LOW.
- The AND operation of two inputs “Source A” and “Source B” is given below. Here, the result is stored in destination address.
- If both the inputs “Source A” and “Source B” are 1, then the output 1 will be displayed on the destination.
- Otherwise, if either of the inputs “Source A” or “Source B” is 0, then the output 0 will be displayed on the destination.
Source A:
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 |
Explanation of Solution
b.
Data stored in the destination address of OR operation:
- In OR operation, the output is always HIGH when any of the inputs are HIGH and the output is LOW when all the inputs are LOW.
- The OR operation of two inputs Source A and Source B is given below. Here, the result is stored in destination address.
- If either of the inputs “Source A” or “Source B” are 1, then the output 1 will be displayed on the destination.
- Otherwise, if both the inputs “Source A” and “Source B” are 0, then the output 0 will be displayed on the destination.
Source A:
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 |
Explanation of Solution
c.
Data stored in the destination address of XOR operation:
- In Exclusive-OR (XOR) operation, the output is always HIGH when either of the inputs is HIGH and the output is LOW when all the inputs are either HIGH or LOW.
- The XOR operation of two inputs Source A and Source B is given below. Here, the result is stored in destination address.
- If either of the inputs “Source A” or “Source B” are 1, then the output 1 will be displayed on the destination.
- Otherwise, if both the inputs “Source A” and “Source B” are 0 or 1, then the output 0 will be displayed on the destination.
Source A:
| 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 1 | 0 | 1 | 0 |
Expert Solution & Answer
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Students have asked these similar questions
I need help fixing the minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
My code is experincing minor issue where the text isn't in the proper place, and to ensure that the frequency cutoff is at the right place.
My code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters - let's adjust these to get more reasonable cutoffs
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
% For bandpass, we need appropriate L value for desired cutoffs
L = 0.1; % Inductance in henries - adjusted for better bandpass response
% Calculate cutoff frequencies first to verify they're in desired range
f_cutoff_RC = 1 / (2 * pi * R * C);
f_resonance = 1 / (2 * pi * sqrt(L * C));
Q_factor = (1/R) * sqrt(L/C);
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Transfer functions
% Low-pass filter (RC)
H_low = 1 ./ (1 + 1i * w *…
I would like to know the main features about the following three concepts:
1. Default forwarded
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3. IP Security (IPSec).
Chapter 4 Solutions
EBK ACTIVITIES MANUAL FOR PROGRAMMABLE
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