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Concept explainers
Logic gate:
- Logic gate is an electronic circuit that is used to take logical decisions based on the input.
- It contains one or more number of inputs and one output.
- The working of logic gate is based on the binary principle that has two states either logic 0 or logic 1.
- The output of logic gate is produced when it satisfies any of its logic conditions.
- The logic condition depends upon the type of the gates and the number of inputs.
- The primary logic gates include AND, OR and NOT and the combinations of these gates are used to implement any of the other logic gates.
AND gate:
- The AND gate refers to a logic gate whose output will be HIGH only when all the inputs are HIGH.
- The output of AND gate will be LOW when any one of its input is LOW.
- The symbol to represent AND gate is given below.
- The truth table for AND gate is as follows.
INPUT A | INPUT B | OUTPUT Y |
0 | 0 | 0 |
0 | 1 | 0 |
1 | 0 | 0 |
1 | 1 | 1 |
OR gate:
- The OR gate refers to a logic gate whose output will be HIGH when any one of its inputs are HIGH.
- The output of AND gate will be LOW when both the inputs are LOW.
- The symbol to represent OR gate is given below.
- The truth table for OR gate is as follows.
INPUT A | INPUT B | OUTPUT Y |
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 1 |
NOT gate:
- The NOT gate refers to a logic gate whose output will be HIGH when it’s input is LOW and whose output will be LOW when it’s input is HIGH.
- The symbol to represent NOT gate is given below.
- The truth table for NOT gate is as follows.
INPUT A | OUTPUT Y |
0 | 1 |
1 | 0 |
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Explanation of Solution
a.
Logic gate circuit:
The logic gate circuit is as follows.
Explanation:
In the above given logic gate circuit,
- The inputs “A” and “B” are connected to logic OR gate and the corresponding output will be (A+B).
- Now, the resultant along with other inputs “C” and “D” are connected to logic AND gate whose output will be Y=(A+B)CD.
Therefore, the Boolean expression for the given logic circuit is Y=(A+B)CD.
Explanation of Solution
b.
Logic gate circuit:
The logic gate circuit is as follows.
Explanation:
In the above given logic gate circuit,
- The inputs “A” and “B” are connected to logic OR gate and the corresponding output will be (A+B).
- The input “C” is connected to logic NOT gate and the corresponding output will be “ˉC”.
- Then, the inputs “ˉC” and “D” are connected to another logic OR gate and the corresponding output will be (ˉC+D).
- Now, the output (A+B) and (ˉC+D) are connected to a logic AND gate whose output will be Y=(A+B)(ˉC+D).
Therefore, the Boolean expression for the given logic circuit is Y=(A+B)(ˉC+D).
Explanation of Solution
c.
Logic gate circuit:
The logic gate circuit is as follows.
Explanation:
In the above given logic gate circuit,
- The inputs “A” and “B” are connected to logic AND gate and the corresponding output will be (AB).
- Now, the resultant along with other input “C” is connected to logic OR gate whose output will be Y=(AB+C).
Therefore, the Boolean expression for the given logic circuit is Y=(AB+C).
Explanation of Solution
d.
Logic gate circuit:
The logic gate circuit is as follows.
Explanation:
In the above given logic gate circuit,
- The inputs “A” and “B” are connected to logic AND gate and the corresponding output will be (AB).
- Now, the resultant along with other input “C” is connected to logic OR gate whose output will be (AB+C).
- The input “E” is connected to logic NOT gate and the corresponding output will be “ˉE”.
- Now, the outputs (AB+C) and ˉE along with the input “D” are connected to a logic AND gate whose output will be Y=[(AB+C)DˉE].
Therefore, the Boolean expression for the given logic circuit is Y=[(AB+C)DˉE].
Explanation of Solution
e.
Logic gate circuit:
The logic gate circuit is as follows.
Explanation:
In the above given logic gate circuit,
- The inputs “A” and “B” are connected to logic OR gate and the corresponding output will be (A+B).
- Then, the inputs “C” and “D” are connected to logic OR gate and the corresponding output will be (C+D).
- Now, the output (A+B) and (C+D) are connected to a logic AND gate whose output will be Y=(A+B)(C+D).
Therefore, the Boolean expression for the given logic circuit is Y=(A+B)(C+D).
Explanation of Solution
f.
Logic gate circuit:
The logic gate circuit is as follows.
Explanation:
In the above given logic gate circuit,
- The input “B” is connected to logic NOT gate and the corresponding output will be “ˉB”.
- The inputs “A” and “ˉB” are connected to logic AND gate and the corresponding output will be (AˉB).
- Similarly, the input “D” is connected to logic NOT gate and the corresponding output will be “ˉD”.
- The inputs “C” and “ˉD” are connected to logic AND gate and the corresponding output will be (CˉD).
- Then, the input “F” is connected to logic NOT gate and the corresponding output will be “ˉF”.
- The inputs “E” and “ˉF” are connected to logic AND gate and the corresponding output will be (EˉF).
- Finally, the outputs AˉB, CˉD and EˉF are connected to a logic OR gate whose output will be Y=(AˉB+CˉD+EˉF).
Therefore, the Boolean expression for the given logic circuit is Y=(AˉB+CˉD+EˉF).
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Chapter 4 Solutions
EBK ACTIVITIES MANUAL FOR PROGRAMMABLE
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