The work done in the irreversible path of the performed experiment is done at 25 ° C has to be determined. Concept Introduction: The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below. w = − P ex Δ V The expression for calculating the work of isothermal expansion is shown below. w = − n R T ln ( V f V i )

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Answer 1

Question

Chapter 4, Problem 4A.6E

(a)

Interpretation Introduction

Interpretation:

The work done in the irreversible path of the performed experiment is done at 25 °C has to be determined.

Concept Introduction:

The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below.

w=−PexΔV

The expression for calculating the work of isothermal expansion is shown below.

w=−nRTln(VfVi)

(b)

Interpretation Introduction

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

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Answer 2

Question

Chapter 4, Problem 4A.6E

(a)

Interpretation Introduction

Interpretation:

The work done in the irreversible path of the performed experiment is done at 25 °C has to be determined.

Concept Introduction:

The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below.

w=−PexΔV

The expression for calculating the work of isothermal expansion is shown below.

w=−nRTln(VfVi)

(b)

Interpretation Introduction

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

Expert Solution & Answer

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Answer 3

Question

Chapter 4, Problem 4A.6E

(a)

Interpretation Introduction

Interpretation:

The work done in the irreversible path of the performed experiment is done at 25 °C has to be determined.

Concept Introduction:

The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below.

w=−PexΔV

The expression for calculating the work of isothermal expansion is shown below.

w=−nRTln(VfVi)

(b)

Interpretation Introduction

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

Expert Solution & Answer

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Answer 4

Question

Chapter 4, Problem 4A.6E

(a)

Interpretation Introduction

Interpretation:

The work done in the irreversible path of the performed experiment is done at 25 °C has to be determined.

Concept Introduction:

The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below.

w=−PexΔV

The expression for calculating the work of isothermal expansion is shown below.

w=−nRTln(VfVi)

(b)

Interpretation Introduction

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

Expert Solution & Answer

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Answer 5

Chapter 4, Problem 4A.6E

(a)

Interpretation Introduction

Interpretation:

The work done in the irreversible path of the performed experiment is done at 25 °C has to be determined.

Concept Introduction:

The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below.

w=−PexΔV

The expression for calculating the work of isothermal expansion is shown below.

w=−nRTln(VfVi)

(b)

Interpretation Introduction

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

Answer 6

Chapter 4, Problem 4A.6E

(a)

Interpretation Introduction

Interpretation:

The work done in the irreversible path of the performed experiment is done at 25 °C has to be determined.

Concept Introduction:

The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below.

w=−PexΔV

The expression for calculating the work of isothermal expansion is shown below.

w=−nRTln(VfVi)

Answer 7

Chapter 4, Problem 4A.6E

(a)

Interpretation Introduction

Interpretation:

The work done in the irreversible path of the performed experiment is done at 25 °C has to be determined.

Concept Introduction:

The system can done two kind of works. The one is the work of expansion which is the work which arises from the change in the volume of the system. On the other hand the second work done is the work of non-expansion which does not involve any change in the volume of the system. The expression for calculating the work of reversible expansion is shown below.

w=−PexΔV

The expression for calculating the work of isothermal expansion is shown below.

w=−nRTln(VfVi)

Answer 8

(b)

Interpretation Introduction

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

Answer 9

(b)

Interpretation Introduction

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

Ch. 4 - Prob. 4A.1AST Ch. 4 - Prob. 4A.1BST Ch. 4 - Prob. 4A.2AST Ch. 4 - Prob. 4A.2BST Ch. 4 - Prob. 4A.3AST Ch. 4 - Prob. 4A.3BST Ch. 4 - Prob. 4A.4AST Ch. 4 - Prob. 4A.4BST Ch. 4 - Prob. 4A.1E Ch. 4 - Prob. 4A.2E

Solution Summary: The author explains the work done in the irreversible path of the performed experiment.

Videos

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).

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Chapter 4 Solutions

Solution Summary: The author explains the work done in the irreversible path of the performed experiment.

Videos

Interpretation: The process in which more work done is done at 25 °C has to be identified. Concept Introduction: Same as part (a).

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Chapter 4 Solutions

Interpretation:

The process in which more work done is done at 25 °C has to be identified.

Concept Introduction:

Same as part (a).