![College Physics (10th Edition)](https://www.bartleby.com/isbn_cover_images/9780321902788/9780321902788_largeCoverImage.gif)
|| Jumping to the ground. A 75.0 kg man steps off a platform 3.10 m above the ground. He keeps his legs straight as he falls, but at the moment his feet touch the ground his knees begin to bend, and, treated as a particle, he moves an additional 0.60 m before coming to rest. (a) What is his speed at the instant his feet touch the ground? (b) Treating him as a particle, what are the magnitude and direction of his acceleration as he slows down if the acceleration is constant? (c) Draw a free-body diagram of this man as he is slowing down. (d) Use Newton's laws and the results of part (b) to calculate the force the ground exerts on him while he is slowing down. Express this force in newtons and also as a multiple of the man's weight. (e) What are the magnitude and direction of the reaction force to the force you found in part (c)?
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Chapter 4 Solutions
College Physics (10th Edition)
Additional Science Textbook Solutions
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Conceptual Physical Science (6th Edition)
Lecture- Tutorials for Introductory Astronomy
Conceptual Integrated Science
Introduction to Electrodynamics
Applied Physics (11th Edition)
- In the blizzard of ’88, a rancher was forced to drop hay bales from an airplane to feed her cattle. The plane flew horizontally at 160 km/hr and dropped the bales from a height of 80 m above the flat range, (a) She wanted the bales of hay to land 30 m behind the cattle so as to not hit them. Where should she push the bales out of the airplane? (b) To not hit the cattle, what is the largest time error she could make while pushing the bales out of the airplane? Ignore air resistance.arrow_forwardAn elevator in the Taipei 101 skyscraper can start fromrest and accelerate to a maximum speed of 16 m>s with a constantacceleration of 1.1 m>s2. Through what distance does the elevatormove as it accelerates to its maximum speed?arrow_forwardHelparrow_forward
- The froghopper, a tiny insect, is a remarkable jumper. Suppose a colony of the little critters is raised on the Moon, where the acceleration due to gravity is only 1.62 m/s2, whereas gravity on Earth is ?=9.81 m/s2. If on Earth a froghopper's maximum jump height is ℎ and its maximum horizontal jump range is ?, what would its maximum jump height and range be on the Moon in terms of ℎ and ?? Assume the froghopper's takeoff velocity is the same on the Moon and Earth.arrow_forward٤٣ B/s ۱۰:۰۹ ص .in the direction of the force TO FO choose the correct answer The acceleration Vector in cartizan Cordinat writin by the formulla Ⓒazé x + j X+kŹ =¿Ÿ+K Ⓒă= cx+jŸ+k² @a=ix + ³y +kż a b с do time derivative of velocity is called acceleration rate velocity docs.google.com/forms/d/ तंarrow_forwardIn the vertical jump, an Kobe Bryant starts from a crouch and jumps upward to reach as high as possible. Even the best athletes spend little more than 1.00 ss in the air (their "hang time"). Treat Kobe as a particle and let ymaxymax be his maximum height above the floor. Note: this isn't the entire story since Kobe can twist and curl up in the air, but then we can no longer treat him as a particle. Hint: Find v0 to reach y_max in terms of g and y_max and recall the velocity at y_max is zero. Then find v1 to reach y_max/2 with the same kinematic equation. The time to reach y_max is obtained from v0=g (t), and the time to reach y_max/2 is given by v1-v0= -g(t1). Now, t1 is the time to reach y_max/2, and the quantity t-t1 is the time to go from y_max/2 to y_max. You want the ratio of (t-t1)/t1 To explain why he seems to hang in the air, calculate the ratio of the time he is above ymax/2ymax/2 moving up to the time it takes him to go from the floor to that height. You may ignore…arrow_forward
- Vmax In a laboratory experiment, a sphere of diameter 8.0 mm is released from rest at t = 0 at the surface of honey in a jar, and the sphere's downward speed v when it travels in the honey is found to be given by v = Vmax (1 - e-t/T), where 0.040 m/s and T = 0.50 s. (a) Obtain an expression for a(t). (b) Draw graphs for v(t) and a(t) for the time interval 0 to 2.0 s. (c) Obtain an expression for x(t), choosing the positive x axis as downward, and draw the graph for this func- tion. (d) Use your x(t) graph to determine the time interval needed for the sphere to reach the bottom of the container if the surface of the honey is 0.10 m above the bottom of the jar. ... =arrow_forwardHW4 - MTH 114, section 1, Sprin X + с https://www.webassign.net/web/Student/Assignment-Responses/submit?dep=31254787&tags=autosave#question3... Q 20 A woman driving a car 16 ft long is passing a truck 28 ft long. The truck is traveling at 50 mi/h. How fast must the woman drive her car so that she can pass the truck completely in 6 s, from the position shown in figure (a) to the position shown in figure (b)? [Hint: Use feet and seconds instead of miles and hours.] mi/h Need Help? Watch It ccess Confirmation of Questio X C Master It + https://www.bartleb.. (a) (b) New tab (Ctrl+T) 50 mi/h 50 mi/h Fb CHAT *** MATH SOLVER A MY NOTES 0 ASK YOUR TEACHER X PRACTICE ANOTHER by 6 mi/h to drive the 132 mi from Barrington to Collins. If the second leg of his trip took 2 min more time than the first leg,arrow_forwardAstronomers have discoveredseveral volcanoes on Io, a moon of Jupiter. One of them, namedLoki, ejects lava to a maximum height of 2.00 * 105 m. (a) Whatis the initial speed of the lava? (The acceleration of gravity on Io is1.80 m>s2.) (b) If this volcano were on Earth, would the maximumheight of the ejected lava be greater than, less than, or the same ason Io? Explain.arrow_forward
- Motion in One -Dimension 3. A rock is released from rest from the top of a very high cliff, and accelerates downward at g. Approximately how far does the rock travel in the first 7 seconds of its free-fall? (Assume no air friction.)arrow_forwardTrue / False: In an elevator the acceleration is magically measured to be -3.00 m/s2 (where + is up and – is down) I therefore know that the elevator is moving down.arrow_forwardIn the vertical jump, an Kobe Bryant starts from a crouch and jumps upward to reach as high as possible. Even the best athletes spend little more than 1.00 s in the air (their "hang time"). Treat Kobe as a particle and let ymax be his maximum height above the floor. Note: this isn't the entire story since Kobe can twist and curl up in the air, but then we can no longer treat him as a particle. Hint: Find v0 to reach y_max in terms of g and y_max and recall the velocity at y_max is zero. Then find v1 to reach y_max/2 with the same kinematic equation. The time to reach y_max is obtained from v0=g (t), and the time to reach y_max/2 is given by v1-v0= -g(t1). Now, t1 is the time to reach y_max/2, and the quantity t-t1 is the time to go from y_max/2 to y_max. You want the ratio of (t-t1)/t1 Note from Asker: I am generally confused on how to manipulate the formulas, so if you could show every step that would be great, Thank You. Part A Part complete To explain why…arrow_forward
- Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill
![Text book image](https://www.bartleby.com/isbn_cover_images/9780534408961/9780534408961_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133104261/9781133104261_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133939146/9781133939146_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305116399/9781305116399_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078807213/9780078807213_smallCoverImage.gif)