Fundamentals Of Engineering Thermodynamics, 9e
9th Edition
ISBN: 9781119391432
Author: MORAN
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 4, Problem 4.81P
a)
To determine
Initial and final mass of air in cavern.
b)
To determine
Work done by the compressor.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A cycle starts with an adiabatic compression of the air from state a with a volume V3 to state b with volume V1. At the end of the compression, heat is added (absorbed), resulting in an isobaric expansion to state c with volume V2 followed by an adiabatic expansion back to volume V3 at state d. Finally, heat is expelled, corresponding to an isochoric reduction completing the cycle and bringing air back to state a.
Find the ratio between the initial and final temperatures for (1) the adiabatic compression, and (2) the adiabatic expansion in terms of the expansion ratio re = V3 /V2 and the compression ratio rc = V3 /V1..
Question #2
For the following processes, find the changes in h as appropriate.
The initial state pressure is p1 = 0.5 MPa. the final state is 2.
a. constant volume : v1 = 0.3 m3/kg, p2 = 0.3 MPa;
b. constant entropy : s1 = 6.3 kJ/kg K, p2 = 0.15 MPa;
c. constant volume : h1 = 2500 kJ/kg, p2 = 0.2 MPa;
d. constant enthalpy : s1 = 6.4 kJ/kg K, p2 = 0.2 MPa;
4.13
Chapter 4 Solutions
Fundamentals Of Engineering Thermodynamics, 9e
Ch. 4 - Prob. 4.1ECh. 4 - Prob. 4.2ECh. 4 - Prob. 4.3ECh. 4 - Prob. 4.4ECh. 4 - Prob. 4.5ECh. 4 - Prob. 4.6ECh. 4 - Prob. 4.7ECh. 4 - Prob. 4.8ECh. 4 - Prob. 4.9ECh. 4 - Prob. 4.10E
Ch. 4 - Prob. 4.11ECh. 4 - Prob. 4.12ECh. 4 - Prob. 4.13ECh. 4 - Prob. 4.14ECh. 4 - Prob. 4.15ECh. 4 - Prob. 4.1CUCh. 4 - Prob. 4.2CUCh. 4 - Prob. 4.3CUCh. 4 - Prob. 4.4CUCh. 4 - Prob. 4.5CUCh. 4 - Prob. 4.6CUCh. 4 - Prob. 4.7CUCh. 4 - Prob. 4.8CUCh. 4 - Prob. 4.9CUCh. 4 - Prob. 4.10CUCh. 4 - Prob. 4.11CUCh. 4 - Prob. 4.12CUCh. 4 - Prob. 4.13CUCh. 4 - Prob. 4.14CUCh. 4 - Prob. 4.15CUCh. 4 - Prob. 4.16CUCh. 4 - Prob. 4.17CUCh. 4 - Prob. 4.18CUCh. 4 - Prob. 4.19CUCh. 4 - Prob. 4.20CUCh. 4 - Prob. 4.21CUCh. 4 - Prob. 4.22CUCh. 4 - Prob. 4.23CUCh. 4 - Prob. 4.24CUCh. 4 - Prob. 4.25CUCh. 4 - Prob. 4.26CUCh. 4 - Prob. 4.27CUCh. 4 - Prob. 4.28CUCh. 4 - Prob. 4.29CUCh. 4 - Prob. 4.30CUCh. 4 - Prob. 4.31CUCh. 4 - Prob. 4.32CUCh. 4 - Prob. 4.33CUCh. 4 - Prob. 4.34CUCh. 4 - Prob. 4.35CUCh. 4 - Prob. 4.36CUCh. 4 - Prob. 4.37CUCh. 4 - Prob. 4.38CUCh. 4 - Prob. 4.39CUCh. 4 - Prob. 4.40CUCh. 4 - Prob. 4.41CUCh. 4 - Prob. 4.42CUCh. 4 - Prob. 4.43CUCh. 4 - Prob. 4.44CUCh. 4 - Prob. 4.45CUCh. 4 - Prob. 4.46CUCh. 4 - Prob. 4.47CUCh. 4 - Prob. 4.48CUCh. 4 - Prob. 4.49CUCh. 4 - Prob. 4.50CUCh. 4 - Prob. 4.51CUCh. 4 - Prob. 4.1PCh. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Prob. 4.4PCh. 4 - Prob. 4.5PCh. 4 - Prob. 4.6PCh. 4 - Prob. 4.7PCh. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10PCh. 4 - Prob. 4.11PCh. 4 - Prob. 4.12PCh. 4 - Prob. 4.13PCh. 4 - Prob. 4.14PCh. 4 - Prob. 4.15PCh. 4 - Prob. 4.16PCh. 4 - Prob. 4.17PCh. 4 - Prob. 4.18PCh. 4 - Prob. 4.19PCh. 4 - Prob. 4.20PCh. 4 - Prob. 4.21PCh. 4 - Prob. 4.22PCh. 4 - Prob. 4.23PCh. 4 - Prob. 4.24PCh. 4 - Prob. 4.25PCh. 4 - Prob. 4.26PCh. 4 - Prob. 4.27PCh. 4 - Prob. 4.28PCh. 4 - Prob. 4.29PCh. 4 - Prob. 4.30PCh. 4 - Prob. 4.31PCh. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - Prob. 4.34PCh. 4 - Prob. 4.35PCh. 4 - Prob. 4.36PCh. 4 - Prob. 4.37PCh. 4 - Prob. 4.38PCh. 4 - Prob. 4.39PCh. 4 - Prob. 4.40PCh. 4 - Prob. 4.41PCh. 4 - Prob. 4.42PCh. 4 - Prob. 4.43PCh. 4 - Prob. 4.44PCh. 4 - Prob. 4.45PCh. 4 - Prob. 4.46PCh. 4 - Prob. 4.47PCh. 4 - Prob. 4.48PCh. 4 - Prob. 4.49PCh. 4 - Prob. 4.50PCh. 4 - Prob. 4.51PCh. 4 - Prob. 4.52PCh. 4 - Prob. 4.53PCh. 4 - Prob. 4.54PCh. 4 - Prob. 4.55PCh. 4 - Prob. 4.56PCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71PCh. 4 - Prob. 4.72PCh. 4 - Prob. 4.73PCh. 4 - Prob. 4.74PCh. 4 - Prob. 4.75PCh. 4 - Prob. 4.76PCh. 4 - Prob. 4.77PCh. 4 - Prob. 4.78PCh. 4 - Prob. 4.79PCh. 4 - Prob. 4.80PCh. 4 - Prob. 4.81PCh. 4 - Prob. 4.82PCh. 4 - Prob. 4.83PCh. 4 - Prob. 4.84PCh. 4 - Prob. 4.85PCh. 4 - Prob. 4.86PCh. 4 - Prob. 4.87PCh. 4 - Prob. 4.88P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Problem 22.3 Air is contained inside a simple piston cylinder device as shown in the figure. It expands from state 1 to state 2 according the process information shown below: State 1: P₁= 200 kPa; ₁ = 0.5 m³; T₁ = 300 K Process 1-2: Expansion process (see graph) where P = 50 kPa + (300 kPa/m³) State 2: P₂ = 350 kPa; ₂ = 1.0 m³ Determine: the work done on or by the air contained in the piston-cylinder device, in kJ (indicate direction, i.e., is the work done on or by the air?) Air P 350 kPa 200 kPa 1 0.5 1.0 Ans: d) 185 kJ <≤ Wnet] ≤ 200 kJ Karrow_forwardCHR 6. An inventor comes to you with a device that produces work. She tells you helium gas at 10 atm and 650 K enters the device and exits at 2 atm and 260 K. Assume an ideal gas with constant specific heat and the surroundings are at 25 C, Cp = 5.2 kJ/kg-K. Is this process possible assuming steady-state operation?arrow_forwardIdentify the Enthalpy of State 1 to 4 (h1, h2, h3 and h4)arrow_forward
- Solve for mas flow rate, and compressor power in horsepower. Step by step solution please thank youarrow_forward4.13arrow_forwardThe figure shows data for a portion of the ducting in a ventilation system operating at steady state. The ducts are well insulated and the pressure is very nearly 1 atm throughout. The volumetric flow rate entering at state 2 is AV2 = 4400 ft3/min. Assume the ideal gas model for air with cp = 0.24 Btu/lb·oR and ignore kinetic and potential energy effects. Determine the temperature of the air at the exit, in oF, and the rate of entropy production within the ducts, in Btu/min·oR.arrow_forward
- Hi, I need to go over this problem, but how do you find To and Po. Can you walk me through every question that I state on the paper? Thanksarrow_forwardA cycle starts with an adiabatic compression of the air from state a with a volume V3 to state b with volume V1. At the end of the compression, heat is added (absorbed), resulting in an isobaric expansion to state c with volume V2 followed by an adiabatic expansion back to volume V3 at state d. Finally, heat is expelled, corresponding to an isochoric reduction completing the cycle and bringing air back to state a. The thermodynamic identity is given by dU = T dS − P dV. The constant values for the entropy during the adiabatic compression and expansion are S1 and S2, respectively. Illustrate the cycle on a T S diagram labelling states a, b, c and d then find an expression for the temperature T as a function of entropy S for the isobaric and isochoric strokes of the cycle (engine).arrow_forwardpls answer correctly the givenarrow_forward
- 2. thermodynamicsarrow_forwardBetween 1-2: Isothermal compression (1st process)Between 2-3: Isometric compression (2nd process)Between 3-1: Adiabatic expansion (3rd process) A cyclic process through which N2 gas, which is considered to be the ideal behaving, is treated, has been described above. In case 1, the volume of gas is 9.6 m3, pressure 200 kPa. Since the pressure in state 3 is 750 kPa, find the work done in the whole process in kJ. Draw the P-V diagram for the cycle.arrow_forwardWhat is the work of the compressor in KJ/kg?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Thermodynamic Availability, What is?; Author: MechanicaLEi;https://www.youtube.com/watch?v=-04oxjgS99w;License: Standard Youtube License