Interpretation:
To determine the metallic elements which are not solids under ordinary laboratory condition.
Concept Introduction:
Periodic table is arrangement of different elements with the help of columns and rows in order to characterize elements with similar properties in same groups such as alkali metals, alkaline earth metals, halides, noble gases,
Element:
An element is a simplest type of a pure substance which is composed of only one type of matter. For examples; silver, gold platinum etc.
Metal:
Metals are hard, shiny, malleable, fusible, and ductile. They are good conductor of heat and electricity. They are located to the left of the periodic table.
Metalloid:
Metalloids have properties of both metals and non-metals. They are in the middle of the periodic table.
Non-metal:
A non-metal has no lustre, with poor electrical and thermal conductivity. They are in right side of the periodic table.
Valence electron: The electrons which are present in the outer most energy level is known as valence electron. Number of valence electrons can be calculated by the group number of the element. Generally, the group number is same as the valance electrons of any elements.

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Chapter 4 Solutions
EBK INTRO.CHEMISTRY (NASTA EDITION)
- Rank these according to stability. CH3 H3C CH3 1 CH3 H3C 1 most stable, 3 least stable O 1 most stable, 2 least stable 2 most stable, 1 least stable O2 most stable, 3 least stable O3 most stable, 2 least stable O3 most stable, 1 least stable CH3 2 CH3 CH3 H₂C CH3 3 CH3 CHarrow_forwardConsider this IR and NMR: INFRARED SPECTRUM TRANSMITTANCE 0.8- 0.6 0.4 0.2 3000 10 9 8 00 HSP-00-541 7 CO 6 2000 Wavenumber (cm-1) сл 5 ppm 4 M Which compound gave rise to these spectra? N 1000 1 0arrow_forwardConsider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> C2H4Cl 2 MW = 26 36.5 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?arrow_forward
- What is the name of the major product of this reaction? OH CH3 H₂SO4, heat 1-methylcyclohexene O2-methyl-1-cyclohexene O 3-mthylcyclohexene 1-methyl-2-cyclohexenearrow_forwardWe added a brown solution of Br2 to one of our products, and the brown color disappeared. This indicated that our product wasarrow_forwardRank the following according to reactivity toward nitration: a) benzene b) bromobenzene c) nitrobenzene d) phenol Od) greatest, c) least Od) greatest, b) least Od) greatest, a) least a) greatest, b) least a) greatest, c) least Oa) greatest, d) least Ob) greatest, a) least O b) greatest, c) least Ob) greatest, d) least O c) greatest, a) least O c) greatest, b) least O c) greatest, d) leastarrow_forward
- O-Nitrophenol was distilled over with the steam in our experiment while the other isomer did not. This is due to: O intramolecular hydrogen bonding in the ortho isomer O intermolecular hydrogen bonding in the the ortho isomer O the ortho isomer has a lower density O the ortho isomer has a lower molecular weightarrow_forwardK 44% Problem 68 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :6: :: :CI: CI CI: :0:0 Select to Add Arrows Select to Add Arrows H H Cl CI: CI CI: Select to Add Arrows Select to Add Arrows H :CI: Alarrow_forwardI I H :0: Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. 0:0 :0: CI ΑΙ :CI: :CI: :0: CI Select to Add Arrows Select to Add Arrows cl. :0: Cl © ハ CI:: CI H CO Select to Add Arrows Select to Add Arrows 10: AI ::arrow_forward
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