Excursions in Modern Mathematics, Books a la carte edition (9th Edition)
9th Edition
ISBN: 9780134469041
Author: Peter Tannenbaum
Publisher: PEARSON
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Chapter 4, Problem 46E
A small country consists of five states: A, B, C, D, and E. The standard quotas for each state are given in Table 4.35.
Table 4-35
| State | A | B | C | D | E |
| Standard quota | 25.49 | 14.52 | 8.48 | 30.71 | 20.8 |
a. Find the number of seats being apportioned.
b. Find the apportionment under the Huntington-Hill method.
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Prove that
Determine the following groups
Homz(QZ) Hom = (Q13,Z)
Homz(Q), Hom/z/nZ, Qt
for neN-
(2) Every factor group of
adivisible group is divisble.
• If R is a Skew ficald (aring with
identity and each non Zero element is
invertible then every R-module is free.
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
A: Tan Latitude / Tan P
A = Tan 04° 30'/ Tan 77° 50.3'
A= 0.016960 803 S CA named opposite to latitude,
except when hour angle between 090° and 270°)
B: Tan Declination | Sin P
B Tan 052° 42.1'/ Sin 77° 50.3'
B = 1.34 2905601 SCB is alway named same as
declination)
C = A + B = 1.35 9866404 S CC correction, A+/- B:
if A and B have same name - add, If
different name- subtract)
=
Tan Azimuth 1/Ccx cos Latitude)
Tan Azimuth = 0.737640253
Azimuth
=
S 36.4° E CAzimuth takes combined
name of C correction and Hour Angle - If LHA
is between 0° and 180°, it is named "west", if
LHA is between 180° and 360° it is named "east"
True Azimuth= 143.6°
Compass Azimuth = 145.0°
Compass Error = 1.4° West
Variation 4.0 East
Deviation: 5.4 West
Chapter 4 Solutions
Excursions in Modern Mathematics, Books a la carte edition (9th Edition)
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Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Find the apportionment under Hamiltons method of...Ch. 4 - Happy Rivers County consists of three towns:...Ch. 4 - Plainville Hospital has three wings A, B, and C....Ch. 4 - The small nation of Fireland is divided into four...Ch. 4 - The Republic of Galatia is divided into four...Ch. 4 - Find the apportionment under Jeffersons method of...Ch. 4 - Find the apportionment under Jeffersons method of...Ch. 4 - Find the apportionment under Jeffersons method of...Ch. 4 - The small republic of Guayuru see Example 4.11...Ch. 4 - Find the apportionment under Jeffersons method of...Ch. 4 - Find the apportionment under Jeffersons method of...Ch. 4 - Find the apportionment under Jeffersons method of...Ch. 4 - Find the apportionment under Jeffersons method of...Ch. 4 - Find the apportionment under Adamss method of the...Ch. 4 - Find the apportionment under Adamss method of the...Ch. 4 - Find the apportionment under Adamss method of the...Ch. 4 - Find the apportionment under Adamss method of the...Ch. 4 - Find the apportionment under Websters method of...Ch. 4 - Find the apportionment under Websters method of...Ch. 4 - Find the apportionment under Websters method of...Ch. 4 - Find the apportionment under Websters method of...Ch. 4 - Find the apportionment under Websters method of...Ch. 4 - Find the apportionment under Websters method of...Ch. 4 - Round each number using the Huntington-Hill...Ch. 4 - Round each number using the Huntington-Hill...Ch. 4 - In the 2010 apportionment of the U.S. House of...Ch. 4 - In the 2010 apportionment of the U.S. House of...Ch. 4 - A small country consists of five states: A, B, C,...Ch. 4 - A small country consists of five states: A, B, C,...Ch. 4 - A small country consists of five states: A, B, C,...Ch. 4 - A small country consists of five states: A, B, C,...Ch. 4 - A country consists of six states, with the states...Ch. 4 - A country consists of six states, with the states...Ch. 4 - If the standard quota of state X is 35.41, then...Ch. 4 - If the standard quota of state Y is 78.24, then...Ch. 4 - If the standard quota of state X is 35.41, then...Ch. 4 - If the standard quota of state Y is 78.24, then...Ch. 4 - If the standard quota of state X is 35.41, then...Ch. 4 - If the standard quota of state Y is 78.24, then...Ch. 4 - At the time of the 2000 Census, Californias...Ch. 4 - At the time of the 2000 Census, Californias...Ch. 4 - This exercise refers to the apportionment of...Ch. 4 - This exercise refers to the apportionment of...Ch. 4 - Exercises 61 and 62 are based on the following...Ch. 4 - Exercises 61 and 62 are based on the following...Ch. 4 - This exercise comes in two parts. Read Part I and...Ch. 4 - This exercise comes in two parts. Read Part I and...Ch. 4 - The small island nation of Margarita consists of...Ch. 4 - Prob. 66ECh. 4 - Prob. 67ECh. 4 - Prob. 68ECh. 4 - Prob. 69ECh. 4 - Consider the problem of apportioning M seats...Ch. 4 - Prob. 71ECh. 4 - Prob. 72ECh. 4 - Lowndess Method. Exercises 73 and 74 refer to a...Ch. 4 - Prob. 74ECh. 4 - Prob. 75ECh. 4 - Explain why the Jeffersons method cannot produce...Ch. 4 - Explain why the Adamss method cannot produce a.the...Ch. 4 - Explain why the Websters method cannot produce...
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- Direction: Strictly write in 4 bond paper, because my activity sheet is have 4 spaces. This is actually for maritime. industry course, but I think geometry can do this. use nautical almanac. Sample Calculation (Amplitude- Sun): On 07th May 2006 at Sunset, a vesel in position 10°00'N 0 10°00' W observed the sun bearing 288° by compass. Find the compass error. LMT Sunset 07d 18h 13m (+)00d 00h 40 м LIT: UTC Sunset: 07d 18h 53 m added - since longitude is westerly Declination Co7d 18h): N016° 55.5' d(0.7): (+) 00-6 N016 56.1' Declination Sun: Sin Amplitude Sin Declination (Los Latitude - Sin 016° 56.1'/Cos 10°00' = 0.295780189 Amplitude = WI. 2N (The prefix of amplitude is named easterly if body is rising. and westerly of body is setting. The suffix is named came as declination.) True Bearing: 287.20 Compass Bearing 288.0° Compass Error: 0.8' Westarrow_forwardOnly 100% sure experts solve it correct complete solutions need to get full marks it's my quiz okkkk.take your time but solve full accurate okkk maths expert solve itarrow_forwardI have ai answers but incorrectarrow_forward
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