Concept explainers
(a)
Interpretation:
The
Concept introduction:
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Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 1
In this case, bromide ion gets priority over chloride ion and iodide ion gets priority over chloride ion. The structure with higher priority order is written as shown below.
Figure 2
The higher priority groups are present on opposite sides of the double bond. As a result,
The configuration of the given structure is
(b)
Interpretation:
The
Concept introduction:
Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as
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Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 3
In this case, the
Figure 4
The higher priority atoms are present on the same side of the double bond. As a result,
The configuration of the given structure is
(c)
Interpretation:
The
Concept introduction:
Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as
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Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 5
In this case, right side of double bond contains
Figure 6
One carbon atom is attached to three carbon atoms and other attached to two carbon atoms. Therefore, the carbon atom which is attached to three carbon atoms gets higher priority. As a result, higher priority atoms are present on opposite sides of the double bond. The structure is assigned
The configuration of the given structure is
(d)
Interpretation:
The
Concept introduction:
Alkenes are the unsaturated class of organic compounds which have a double bond in their structure. The general formula of alkene is written as
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Answer to Problem 4.47AP
The configuration assigned to the given structure is
Explanation of Solution
The
Figure 7
In this case, left and right side of the double bond contains a carbon atoms cyclic ring whose priority order is identified on the basis of higher priority order atoms attached to its carbon atom which is marked as shown below.
Figure 8
On both sides, One carbon atom is attached to three carbon atoms and other attached to two carbon atoms. Therefore, the carbon atom which is attached to three carbon atoms gets higher priority. Along with double bond get higher priority over the single bond. As a result, higher priority atoms are present on opposite sides of the double bond. The structure is assigned
The configuration of the given structure is
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Chapter 4 Solutions
EBK ORGANIC CHEMISTRY STUDY GUIDE AND S
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- Give the major product of the following reaction. excess 1. OH, H₂O 1.OH H CH3CH2CH21 H 2. A.-H₂O Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default.arrow_forward2. Use Hess's law to calculate the AH (in kJ) for: rxn CIF(g) + F2(g) → CIF 3 (1) using the following information: 2CIF(g) + O2(g) → Cl₂O(g) + OF 2(g) AH = 167.5 kJ ΔΗ 2F2 (g) + O2(g) → 2 OF 2(g) 2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g) о = = -43.5 kJ AH = 394.1kJarrow_forwardci Draw the major product(s) of the following reactions: (3 pts) CH3 HNO3/H2SO4 HNO3/ H2SO4 OCH3 (1 pts)arrow_forward
- What is the molecular formula of the bond-line structure shown below OH HO ○ C14H12O2 ○ C16H14O2 ○ C16H12O2 O C14H14O2arrow_forwardCheck all molecules that are acids on the list below. H2CO3 HC2H3O2 C6H5NH2 HNO3 NH3arrow_forwardFrom the given compound, choose the proton that best fits each given description. a CH2 CH 2 Cl b с CH2 F Most shielded: (Choose one) Least shielded: (Choose one) Highest chemical shift: (Choose one) Lowest chemical shift: (Choose one) ×arrow_forward
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