Concept explainers
(a)
Interpretation:
Noble gas having an electron configuration identical to that of the following ion -
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.
(b)
Interpretation:
Noble gas having an electron configuration identical to that of the following ion -
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.
(c)
Interpretation:
Noble gas having an electron configuration identical to that of the following ion -
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.
(d)
Interpretation:
Noble gas having an electron configuration identical to that of the following ion -
Concept Introduction:
Atoms tend to gain or lose electrons until they obtain an electron configuration that is the same as that of a noble gas.
The neutral atom has equal number of protons and electrons. Gaining or loosing of a electrons of an atoms form ions.
Atoms form their ions to attain noble gas configuration.
- Group IA, IIA and IIIA are metal atoms containing one, two or three valence electrons. These metal atoms lose their valence electrons to get noble gas configuration.
- Group VA, VIA VIIA are non-metal atoms containing five, six or seven valence electrons. These non-metal atoms acquire electrons to get noble gas configuration.
- Group IVA group elements have four valence electrons. These elements either gain or lose their electrons to get noble gas configuration.

Want to see the full answer?
Check out a sample textbook solution
Chapter 4 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- Determine if the following salt is neutral, acidic or basic. If acidic or basic, write the appropriate equilibrium equation for the acid or base that exists when the salt is dissolved in aqueous solution. If neutral, simply write only NR. Be sure to include the proper phases for all species within the reaction. N₂H₅ClO₄arrow_forwardPlease help me with identifying these.arrow_forwardCan I please get help with this?arrow_forward
- Can I please get help with identifying these?arrow_forward4. Calculate the pH of a 0.10 M acetic acid (CH3COOH) solution if the Ka of acetic acid = 1.8 x 10-5arrow_forwardDraw the Zaitsev product of the dehydration of this alcohol. + I X 5 OH ざ~ TSOH Click and drag to start drawing a structure.arrow_forward
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning




