Chapter 4, Problem 4.42E

Calculate the mass in grams of positive ions and negative ions contained in $1\text{mol}$ of each compound given in Exercise 4.38.

Interpretation Introduction

(a)

Interpretation:

The mass in grams of positive ions and negative ions present in the given compound are to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer to Problem 4.42E

The mass of positive ions and negative ions present in $\text{NaBr}$ is $22.99\text{g}$ and $79.90\text{g}$ respectively.

Explanation of Solution

The given compound is $\text{NaBr}$.

One mole of $\text{NaBr}$ compound contains one ${\text{Na}}^{+}$ cation and one ${\text{Br}}^{-}$ anion. The mass of one mole of ${\text{Na}}^{+}$ cation is $22.99\text{g}$ and one mole of ${\text{Br}}^{-}$ anion is $79.90\text{g}$.

The mass of one mole of ${\text{Na}}^{+}$ cation is $\begin{array}{rll}& =& 1\text{mol}\times 22.99\text{g}/\text{mol}\\ & =& 22.99\text{g}\end{array}$

The mass of one mole of ${\text{Br}}^{-}$ anion is $\begin{array}{rll}& =& 1\text{mol}\times 79.90\text{g}/\text{mol}\\ & =& 79.90\text{g}\end{array}$

The mass of positive ions and negative ions present in $\text{NaBr}$ is $22.99\text{g}$ and $79.90\text{g}$ respectively.

Conclusion

The mass of positive ions and negative ions present in $\text{NaBr}$ is $22.99\text{g}$ and $79.90\text{g}$ respectively.

Interpretation Introduction

(b)

Interpretation:

The mass in grams of positive ions and negative ions present in the given compound are to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer to Problem 4.42E

The mass of positive ions and negative ions present in ${\text{CaF}}_2$ is $40.08\text{g}$ and $38.00\text{g}$ respectively.

Explanation of Solution

The given compound is ${\text{CaF}}_2$.

One mole of ${\text{CaF}}_2$ compound contains one ${\text{Ca}}^{2+}$ cation and two ${\text{F}}^{-}$ anions. The mass of one mole of ${\text{Ca}}^{2+}$ cation is $40.08\text{g}$ and one mole of ${\text{F}}^{-}$ anion is $19.00\text{g}$.

The mass of one mole of ${\text{Ca}}^{2+}$ cation is $\begin{array}{rll}& =& 1\text{mol}\times 40.08\text{g}/\text{mol}\\ & =& 40.08\text{g}\end{array}$

The mass of two moles of ${\text{F}}^{-}$ anion is $\begin{array}{rll}& =& 1\text{mol}\times 19.00\text{g}/\text{mol}\\ & =& 38.00\text{g}\end{array}$

The mass of positive ions and negative ions present in ${\text{CaF}}_2$ is $40.08\text{g}$ and $38.00\text{g}$ respectively.

Conclusion

The mass of positive ions and negative ions present in ${\text{CaF}}_2$ is $40.08\text{g}$ and $38.00\text{g}$ respectively.

Interpretation Introduction

(c)

Interpretation:

The mass in grams of positive ions and negative ions present in the given compound are to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer to Problem 4.42E

The mass of positive ions and negative ions present in ${\text{Cu}}_2\text{S}$ is $127.1\text{g}$ and $32.06\text{g}$ respectively.

Explanation of Solution

The given compound is ${\text{Cu}}_2\text{S}$.

One mole of ${\text{Cu}}_2\text{S}$ compound contains two ${\text{Cu}}^{+}$ cations and one ${\text{S}}^{2-}$ anion. The mass of one mole of ${\text{Cu}}^{+}$ cation is $63.55\text{g}$ and one mole of ${\text{S}}^{2-}$ anion is $32.06\text{g}$.

The mass of two moles of ${\text{Cu}}^{+}$ cation is $\begin{array}{rll}& =& 2\text{mol}\times 63.55\text{g}/\text{mol}\\ & =& 127.1\text{g}\end{array}$

The mass of one mole of ${\text{S}}^{2-}$ anion is $\begin{array}{rll}& =& 1\text{mol}\times 32.06\text{g}/\text{mol}\\ & =& 32.06\text{g}\end{array}$

The mass of positive ions and negative ions present in ${\text{Cu}}_2\text{S}$ is $127.1\text{g}$ and $32.06\text{g}$ respectively.

Conclusion

The mass of positive ions and negative ions present in ${\text{Cu}}_2\text{S}$ is $127.1\text{g}$ and $32.06\text{g}$ respectively.

Interpretation Introduction

(d)

Interpretation:

The mass in grams of positive ions and negative ions present in the given compound are to be calculated.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. The binary ionic compounds are composed of only one cation and one anion.

Answer to Problem 4.42E

The mass of positive ions and negative ions present in ${\text{Li}}_{\text{3}}\text{N}$ is $20.8\text{g}$ and $14.01\text{g}$ respectively.

Explanation of Solution

The given compound is ${\text{Li}}_{\text{3}}\text{N}$.

One mole of ${\text{Li}}_{\text{3}}\text{N}$ compound contains three ${\text{Li}}^{+}$ cations and one ${\text{N}}^{3-}$ anion. The mass of one mole of ${\text{Li}}^{+}$ cation is $6.94\text{g}$ and one mole of ${\text{N}}^{3-}$ anion is $14.01\text{g}$.

The mass of three moles of ${\text{Li}}^{+}$ cation is $\begin{array}{rll}& =& 3\text{mol}\times 6.94\text{g}/\text{mol}\\ & =& 20.8\text{g}\end{array}$

The mass of one mole of ${\text{N}}^{3-}$ anion is $\begin{array}{rll}& =& 1\text{mol}\times 14.01\text{g}/\text{mol}\\ & =& 14.01\text{g}\end{array}$

The mass of positive ions and negative ions present in ${\text{Li}}_{\text{3}}\text{N}$ is $20.8\text{g}$ and $14.01\text{g}$ respectively.

Conclusion

The mass of positive ions and negative ions present in ${\text{Li}}_{\text{3}}\text{N}$ is $20.8\text{g}$ and $14.01\text{g}$ respectively.