Chapter 4, Problem 4.33P

Interpretation Introduction

Interpretation:

For a hydrogen molecule that travels at a speed of $2.0\times {10}^3\text{m}\cdot {\text{s}}^{-1}$ with mass of $3.35\times {10}^{-27}\text{kg}$, de Broglie wavelength has to be calculated.

Concept Introduction:

Light has a dual nature.  They have wave like nature and also particle-like nature.  De Broglie wavelength of particle can be calculated using the equation given below.

    $\lambda =\frac{h}{p}$

Where,

    $\lambda$ is the De Broglie wavelength.

    $h$ is the Planck’s constant ($6.626\times {10}^{-34}\text{J}\cdot \text{s}$).

    $p$ is the momentum of particle.

Momentum of any object is equal to the product of its mass and speed.  Therefore, the De Broglie wavelength equation can be also written as shown below.

    $\lambda =\frac{h}{mv}$