Process Dynamics and Control, 4e
4th Edition
ISBN: 9781119285915
Author: Seborg
Publisher: WILEY
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Question
Chapter 4, Problem 4.2E
Interpretation Introduction
(a)
Interpretation:
The steady-state gain of the equation
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has been attended by a given unit step in the input.
Interpretation Introduction
(b)
Interpretation:
The time constant needs to be determined.
Concept introduction:
The time constant usually is denoted by using the Greek letter
Interpretation Introduction
(c)
Interpretation:
The value of the output
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
Interpretation Introduction
(d)
Interpretation:
The value of output needs to be determined, when
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
Interpretation Introduction
(e)
Interpretation:
The value of the output needs to be determined.
Concept introduction:
A final value theorem requires the time domain actions to be determined simply by taking a maximum of a frequency domain expression, as opposed to translating by adding the limit to a time-domain expression.
Interpretation Introduction
(f)
Interpretation:
The output value of the given equation if
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
Interpretation Introduction
(g)
Interpretation:
The output value of the given equation needs to be determined, if
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
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Example A continuous fractionating column is to be design to separate 30 Ib/h of a mixture of 40 percent benzene and 60 percent toluene into an overhead product containing 97 percent benzene and a bottom product containing 98 percent toluene. These percentages are by weight. A reflux ratio of 3.5 mol to 1 mol of product is to be used. The molal latent heats of benzene and toluene are 7,360 and 7,960 cal/mol, respectively. Benzene and toluene form an ideal system with a relative volatility of about 2.5; the equilibrium curve is shown in Figure below. The feed has a boiling point of 95 °C at a pressure of 1 atm.
(a) Calculate the moles of overhead product and bottom product per hour.
(b) Determine the number of ideal plate and the position of the feed plate:
(i) if the feed is liquid and at its boiling point.
(ii)if the feed is liquid and at 20 °C (specific heat 0.44 cal/ g.°C) (iii) if the feed is a mixture of two-thirds vapor and one-third liquid.
(c) If steam at 20 Ib/in? (1.36 atm)…
Hydrogen, important for numerous processes, can be produced by the shift reaction:
CO+H2O-CO2 +H2
In the reactor system shown in the Figure, the conditions of conversion have been adjusted so
that the H2 content of the effluent from the reactor is 3 mol %. Based on the data in following
figure:
a. Calculate the composition of the fresh feed.
b. Calculate the moles of recycle per mole of hydrogen produced.
Recycle
CO, H2O
Feed
CO
H₂O
Reactor
%
3 mol %
H₂
Separator
%
CO₂ 48
H₂ 48
CO 4
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