(a)
Interpretation:
The steady-state gain of the equation
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has been attended by a given unit step in the input.
(b)
Interpretation:
The time constant needs to be determined.
Concept introduction:
The time constant usually is denoted by using the Greek letter
(c)
Interpretation:
The value of the output
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
(d)
Interpretation:
The value of output needs to be determined, when
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
(e)
Interpretation:
The value of the output needs to be determined.
Concept introduction:
A final value theorem requires the time domain actions to be determined simply by taking a maximum of a frequency domain expression, as opposed to translating by adding the limit to a time-domain expression.
(f)
Interpretation:
The output value of the given equation if
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
(g)
Interpretation:
The output value of the given equation needs to be determined, if
Concept introduction:
Steady-state gain is the steady-state value of transfer function which has attended by given unit step in the input.
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Check out a sample textbook solution- Q2/ An adsorption study is set up in laboratory by adding a known amount of activated carbon to six which contain 200 mL of an industrial waste. An additional flask containing 200 mL of waste but no c is run as a blank. Plot the Langmuir isotherm and determine the values of the constants. Flask No. Mass of C (mg) Volume in Final COD Flask (mL) (mg C/L) 1 804 200 4.7 2 668 200 7.0 3 512 200 9.31 4 393 200 16.6 C 5 313 200 32.5 6 238 200 62.8 7 0 200 250arrow_forwardمشر on ۲/۱ Two rods (fins) having same dimensions, one made of brass(k=85 m K) and the other of copper (k = 375 W/m K), having one of their ends inserted into a furnace. At a section 10.5 cm a way from the furnace, the temperature brass rod 120°C. Find the distance at which the same temperature would be reached in the copper rod ? both ends are exposed to the same environment. 22.05 ofthearrow_forward4.59 Using the unilateral z-transform, solve the following difference equations with the given initial conditions. (a) y[n]-3y[n-1] = x[n], with x[n] = 4u[n], y[− 1] = 1 (b) y[n]-5y[n-1]+6y[n-2]= x[n], with x[n] = u[n], y[-1] = 3, y[-2]= 2 Ans. (a) y[n] = -2+9(3)", n ≥ -1 (b) y[n]=+8(2)" - (3)", n ≥ -2arrow_forward
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