A. (35 pts) You are part of a team tasked with designing an absorption column in an oil refinery. The team has tasked you to determine the flooding velocity (ft/s) and column diameter (ft) for the following conditions of a hydrocarbon absorber equipped with sieve trays. The graph needed is provided at the end of this document. 3. (8 pts) What is FLG? Pressure 21,000 mm Hg Temperature 55 °C Gas Flowrate - 565 mol/s Gas MW-26.6 g/mol Gas Density 3.1 g/L Liquid Flowrate - 890 mol/s Liquid MW-109 g/mol Liquid Density - 658.4 g/L Liquid Surface Tension – 18.4 dynes/cm Tray Spacing 24 in 4. (8 pts) What is CSB (ft/s)? 5. (8 pts) What is uf (ft/s)? 6. (2 pts) What is uop (ft/s)? 8 = 0.9 Uop = 0.7* Uf 28.32 L = 1 ft³ 7. (9 pts) What is DT (ft) [Do not round up to the nearest half foot]? CSB = ur (20/G)º-2 [PG/(PL-PG)] 0.5 ft/s 0.7 0.6 05 0.4 03 02 88888 0.1 0.07 0.06 0.05 Q04 0.03 0.01 Tray spacing 36" コート 24 18" 12 0.02 0.03 0.05 007 0.1 0.2 Q3 Q.5 0.7 10 2.0 FLG = (L/G)(M/MG)(pg/p₁)0.5
A. (35 pts) You are part of a team tasked with designing an absorption column in an oil refinery. The team has tasked you to determine the flooding velocity (ft/s) and column diameter (ft) for the following conditions of a hydrocarbon absorber equipped with sieve trays. The graph needed is provided at the end of this document. 3. (8 pts) What is FLG? Pressure 21,000 mm Hg Temperature 55 °C Gas Flowrate - 565 mol/s Gas MW-26.6 g/mol Gas Density 3.1 g/L Liquid Flowrate - 890 mol/s Liquid MW-109 g/mol Liquid Density - 658.4 g/L Liquid Surface Tension – 18.4 dynes/cm Tray Spacing 24 in 4. (8 pts) What is CSB (ft/s)? 5. (8 pts) What is uf (ft/s)? 6. (2 pts) What is uop (ft/s)? 8 = 0.9 Uop = 0.7* Uf 28.32 L = 1 ft³ 7. (9 pts) What is DT (ft) [Do not round up to the nearest half foot]? CSB = ur (20/G)º-2 [PG/(PL-PG)] 0.5 ft/s 0.7 0.6 05 0.4 03 02 88888 0.1 0.07 0.06 0.05 Q04 0.03 0.01 Tray spacing 36" コート 24 18" 12 0.02 0.03 0.05 007 0.1 0.2 Q3 Q.5 0.7 10 2.0 FLG = (L/G)(M/MG)(pg/p₁)0.5
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
answer choices
3. A. 0.18, B. 0.44, C. 0.01, D. 2
4. A. 0.2, B. 01, C. 0.4, D. 0.065
5.A. 1.43, B. 5.72, C. 0.93, D. 2.86
6. A. 1.0, B. 4.0, . 2.0, D. 0.65
7.A. 15.5, B. 8.0, C. 11.0, D. 58.5
![A. (35 pts) You are part of a team tasked with designing an absorption column in an oil refinery. The
team has tasked you to determine the flooding velocity (ft/s) and column diameter (ft) for the following
conditions of a hydrocarbon absorber equipped with sieve trays. The graph needed is provided at the
end of this document.
3. (8 pts) What is FLG?
Pressure 21,000 mm Hg
Temperature 55 °C
Gas Flowrate - 565 mol/s
Gas MW-26.6 g/mol
Gas Density 3.1 g/L
Liquid Flowrate - 890 mol/s
Liquid MW-109 g/mol
Liquid Density - 658.4 g/L
Liquid Surface Tension – 18.4 dynes/cm
Tray Spacing 24 in
4. (8 pts) What is CSB (ft/s)?
5. (8 pts) What is uf (ft/s)?
6. (2 pts) What is uop (ft/s)?
8 = 0.9
Uop = 0.7* Uf
28.32 L = 1 ft³
7. (9 pts) What is DT (ft) [Do not round up to the nearest half foot]?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb957c537-60c7-415f-b6cc-9e02c08b1c01%2F472f16c7-4249-4426-8619-65eb6625d8e0%2Fpb03w3_processed.png&w=3840&q=75)
Transcribed Image Text:A. (35 pts) You are part of a team tasked with designing an absorption column in an oil refinery. The
team has tasked you to determine the flooding velocity (ft/s) and column diameter (ft) for the following
conditions of a hydrocarbon absorber equipped with sieve trays. The graph needed is provided at the
end of this document.
3. (8 pts) What is FLG?
Pressure 21,000 mm Hg
Temperature 55 °C
Gas Flowrate - 565 mol/s
Gas MW-26.6 g/mol
Gas Density 3.1 g/L
Liquid Flowrate - 890 mol/s
Liquid MW-109 g/mol
Liquid Density - 658.4 g/L
Liquid Surface Tension – 18.4 dynes/cm
Tray Spacing 24 in
4. (8 pts) What is CSB (ft/s)?
5. (8 pts) What is uf (ft/s)?
6. (2 pts) What is uop (ft/s)?
8 = 0.9
Uop = 0.7* Uf
28.32 L = 1 ft³
7. (9 pts) What is DT (ft) [Do not round up to the nearest half foot]?
![CSB = ur (20/G)º-2 [PG/(PL-PG)] 0.5 ft/s
0.7
0.6
05
0.4
03
02
88888
0.1
0.07
0.06
0.05
Q04
0.03
0.01
Tray spacing
36"
コート
24
18"
12
0.02 0.03
0.05 007 0.1
0.2 Q3
Q.5 0.7 10
2.0
FLG = (L/G)(M/MG)(pg/p₁)0.5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb957c537-60c7-415f-b6cc-9e02c08b1c01%2F472f16c7-4249-4426-8619-65eb6625d8e0%2Fyep6qmg_processed.png&w=3840&q=75)
Transcribed Image Text:CSB = ur (20/G)º-2 [PG/(PL-PG)] 0.5 ft/s
0.7
0.6
05
0.4
03
02
88888
0.1
0.07
0.06
0.05
Q04
0.03
0.01
Tray spacing
36"
コート
24
18"
12
0.02 0.03
0.05 007 0.1
0.2 Q3
Q.5 0.7 10
2.0
FLG = (L/G)(M/MG)(pg/p₁)0.5
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