Engineering Electromagnetics
9th Edition
ISBN: 9781260029963
Author: Hayt
Publisher: MCG
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Chapter 4, Problem 4.28P
To determine
The difference in potential between points at
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Consider a closed triangular box resting within a horizontal electric field of magnitude E = 6.86 × 104 N/C as shown in the figure below.
30.0 cm
A closed right triangular box with its vertical side on the left and
downward slope on the right rests within a horizontal electric field
vector E that points from left to right. The box has a height of 10.0 cm
and a depth of 30.0 cm. The downward slope of the box makes an
angle of 60 degrees with the vertical.
(a) Calculate the electric flux through the vertical rectangular surface of the box.
kN • m?/c
(b) Calculate the electric flux through the slanted surface of the box.
kN • m?/c
(c) Calculate the electric flux through the entire surface of the box.
kN • m2/c
Quèstion 3
The presence of many alignments of magnetic dipole moment is given by which materials?
Paramagnetic
Diamagnetic
Ferromagnetic
None of these
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Please explain in detail. Thanks!
Chapter 4 Solutions
Engineering Electromagnetics
Ch. 4 - Given E = Exax + Eyay + Ez3z V/m, where EX, Ey,...Ch. 4 - A positive point charge of magnitude q1 lies at...Ch. 4 - Given E=Epap+Ea+Ez+azV/m, where Ep, E and E2 are...Ch. 4 - An electric field in free space is given by...Ch. 4 - Consider the vector field G = (A/p) aa where A is...Ch. 4 - A electric field in free space is given as...Ch. 4 - Prob. 4.7PCh. 4 - Given E=-xax+yay,(a) find the work involved in...Ch. 4 - An electric field intensity in spherical...Ch. 4 - A sphere of radios a carries a surface density of...
Ch. 4 - At large distances from a dipole antenna (to be...Ch. 4 - Prob. 4.12PCh. 4 - Thee identical point charges of 4 pC each are...Ch. 4 - Given the electric field E=(y+1)ax+(x1)ay+2az find...Ch. 4 - Two uniform lines, 8 nC/m, are located at x=1, z=2...Ch. 4 - A spherically symmetric charge distribution in...Ch. 4 - Uniform surface charge densities of 6 and 2 nC/m2...Ch. 4 - Find the potential at the origin produced by a...Ch. 4 - Volume charge density is given as pv=poer/C/m3,...Ch. 4 - En a certain medium, the electric potential is...Ch. 4 - Prob. 4.21PCh. 4 - A Line charge of infinite length lies along the z...Ch. 4 - Prob. 4.23PCh. 4 - A certain spherically symmetric charge...Ch. 4 - Consider an electric field intensity in free space...Ch. 4 - Let us assume that we have a very thin, square,...Ch. 4 - By performing an appropriate Line integral from...Ch. 4 - Prob. 4.28PCh. 4 - A dipole having a moment P=3ax-5ay+10aznC.m is...Ch. 4 - Prob. 4.30PCh. 4 - A potential field in free space is expressed as...Ch. 4 - Prob. 4.32PCh. 4 - Prob. 4.33PCh. 4 - A sphere of radius a contains volume charge of...Ch. 4 - Four 0.8 nC point charge are located in free space...Ch. 4 - Surface charge of uniform density ps lies on a...
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- A Moving to another question will save this response. Question 9 The presence of a few negative alignments of magnetic dipole moment is given by which materials? Paramagnetic Diamagnetic Ferromagnetic None of these A Moving to another question will save this response. MacBook Air 20 000 esc F2 F3 F4 F5 2# % %24arrow_forwardA thin conducting wire is bent into the shape shown in the figure. The circular portion of the wire has radius 16.0 cm. The wire is in the plane of the screen and carries a current 3.50 A. What is the magnetic field at the center of the loop? (Give the magnitude in μT and select the direction from the options provided.) magnitude direction I -Select--- uT R 3arrow_forwardConsider a time-varying electric field intensity E = E cos(wt - Bz) that exists everywhere in free space. Use Faraday's law to determine the corresponding magnetic field intensity H. You may assume there is no DC (constant) component. Use Ampère's law on your expression for H to find E and solve for ß in terms of w.arrow_forward
- Quèstion 10 The presence of many alignments of magnetic dipole moment is given by which materials? Ferromagnetic Diamagnetic Paramagnetic None of these Click Submit to complete this assessment. Windows bu Windows Au JUbEV IJ ENG 中 US 25°C ho T-T/IT/TV Chparrow_forwardQ5. Consider two magnetic fields given by (a)B = 3x²y – 4xz + 5z2 and (b) B =constant. Comment on these magnetic fields.arrow_forwardImportant: You need to show calculations and steps of your solutions.arrow_forward
- 8. A -6nC particle is moving at 4.0x10^4 m/s along the positive z-axis. It passes a region undeflected where there is uniform electric and magnetic fields. The electric field is 5.75 x 10^5 N/C along the negative x-axis. What is the magnitude and direction of the magnetic field?arrow_forwardTwo charges qa=5uc and qb=8.5 uc are separated by a distance of 15 cm. point p is located along the line segment joining two charges. how far is point p from qa if the magnitude of the electric field at poin p due to the two charges is equal to zero? Draw a sketch of the problem and label appropriatelyarrow_forwardThe expression of a poten tiel field V = 2x²+4y°z is follaus, as gruen %3D Determine the magai tule of the electric field intersity vector E at the point (2,4.3) and the field intensity unit vector in t he disection of the electric at the samearrow_forward
- A cube of side 50cm and it placed in a uniform electric field E = 4} + 2k . Find out electric flux for all faces of the cube. [ You must draw the cube with axes] Derive expression for electric field due to a dipole. Modify the expression whenarrow_forwardQ#05: Apply Gauss's law to the Gaussian surfaces S1. Sz and S, in figure to calculate the electric field between and outside the material. aodel case Ring" s and stween iform. ssian Sa rom SAarrow_forwardDetermine the relationship between Coulomb’s Law and Gauss Law and explain it briefly.arrow_forward
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