Chapter 4, Problem 4.23QP

Interpretation Introduction

Interpretation: The volumes of the samples containing DDT and the corresponding mass of DDT present in the samples are given. The concentration of DDT are to be expressed in $\text{ppm}$ and millimoles per liter.

Concept introduction: One $\text{ppm}$ is equal to milligrams of the substance present in one liter of the solution.

The concentration of the solution in $\text{ppm}$ of the solution is calculated by the formula,

$\text{Concentration}=\frac{\text{Miligrams}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\text{in}\text{liters}}$

The number of millimoles is calculated by the formula,

$\text{Number}\text{of}\text{millimoles}=\frac{\text{Mass}\text{in}\text{mg}}{\text{Molar}\text{mass}}$

The concentration in DDT in millimoles per liter of the solution is calculated by the formula,

$\text{Concentration}=\frac{\text{Millimoles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\text{in}\text{liters}}$

To determine: The concentration of DDT in $\text{ppm}$ and millimoles per liter.