Chapter 4, Problem 4.123AP

(a)

Interpretation Introduction

Interpretation: The molarity of C is to be calculated. The volume to prepare $\text{0}\text{.250}\text{L}$ of $\text{2}\text{.00}\text{M}\text{HCl}$ is to be calculated. The mass of sodium hydrogen carbonate to neutralize $\text{1}\text{.75}\text{L}$ of concentrated $\text{HCl}$ is to be calculated.

Concept introduction: The number of given moles of solute divided by a liter of solution is termed as molarity. It can be given by the formula,

$\text{Molarity}=\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}\left(\text{L}\right)}$

To determine: The molarity of concentrated $\text{HCl}$.

(b)

Interpretation Introduction

To determine: The volume of $36\%$ $\text{HCl}$ required to prepare $\text{0}\text{.250}\text{L}$ of $\text{2}\text{.00}\text{M}\text{HCl}$.

(c)

Interpretation Introduction

To determine: The mass sodium hydrogen carbonate required to neutralize $1.75\text{mL}$ of concentrated $\text{HCl}$.