EBK INTRODUCTION TO HEALTH PHYSICS, FIF
EBK INTRODUCTION TO HEALTH PHYSICS, FIF
5th Edition
ISBN: 9780071835268
Author: Johnson
Publisher: VST
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Chapter 4, Problem 4.1P
To determine

The kinetic energy of the beta particle.

Expert Solution & Answer
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Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

  K.Mmax=[mPma]c2=[14.00324198914.003074004]×(3×108)2=2.5248×1014J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

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The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
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