The kinetic energy of the beta particle.

Question

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Answer 1

Question

Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Expert Solution & Answer

Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

K.Mmax=[mP−ma]c2=[14.003241989−14.003074004]×(3×108)2=2.5248×10−14J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

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Answer 2

Question

Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Expert Solution & Answer

Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

K.Mmax=[mP−ma]c2=[14.003241989−14.003074004]×(3×108)2=2.5248×10−14J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

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Answer 3

Question

Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Expert Solution & Answer

Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

K.Mmax=[mP−ma]c2=[14.003241989−14.003074004]×(3×108)2=2.5248×10−14J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

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Answer 4

Question

Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Expert Solution & Answer

Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

K.Mmax=[mP−ma]c2=[14.003241989−14.003074004]×(3×108)2=2.5248×10−14J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Expert Solution & Answer

Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

K.Mmax=[mP−ma]c2=[14.003241989−14.003074004]×(3×108)2=2.5248×10−14J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

Answer 6

Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Expert Solution & Answer

Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

K.Mmax=[mP−ma]c2=[14.003241989−14.003074004]×(3×108)2=2.5248×10−14J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

Answer 7

Chapter 4, Problem 4.1P

To determine

The kinetic energy of the beta particle.

Answer 8

Expert Solution & Answer

Answer to Problem 4.1P

Kinetic energy of beta particle = 156.875 keV.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given Information:

Atomic mass of parent beta particle = 14.003241989

Atomic mass of daughter beta particle = 14.003074004

Energy of beta particle is equivalent to a change in masses of the atomic element.

K.Mmax=[mP−ma]c2=[14.003241989−14.003074004]×(3×108)2=2.5248×10−14J=157.598 keV.

Conclusion:

Most energetic Beta particles have a kinetic energy of 157.598 keV.

Answer 12

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The kinetic energy of the beta particle.

Concept explainers

The kinetic energy of the beta particle.

Answer to Problem 4.1P

Explanation of Solution

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Chapter 4 Solutions