COMPUTER ORGANIZATION+DESIGN >I<
COMPUTER ORGANIZATION+DESIGN >I<
5th Edition
ISBN: 9781541868397
Author: Patterson
Publisher: ZYBOOKS (CC)
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Chapter 4, Problem 4.19.4E

Explanation of Solution

Impact of the change that is made:

Before change:

When the registers are read the control unit will decode the instruction that is present.

After change:

The register read and latencies of the control that are performed cannot be overlapped

Since overlap is not supported, the latency of the stage ID will be increased.

This increase could affect the clock cycle time of the processor.

Consider if the stage ID tends to be with longest latency.

Impact of change in the performance:

The impact of the change in the performance could be as shown below:

Cycle time before change:

The cycle time before the change will be 250ps at the stage Mem made during the D-Mem read or write operation.

Cycle time after change:

The cycle time after the change is computed as the sum of the control unit and the registers read and write operation...

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Solve the following questions by WRITING YOUR INSTRUCTION CODE in Assembly language. 1. Modify the Lab 4 Tutorial 1 to allow USERS TO ENTER the following parameter and displaythefinal result. You are also required to store the results in the memory named ‘output’. Findthesum of the last four numbers in the array. For example, assume the value of n is 10, the sumwillbe 10+9+8+7= 34 (in decimal). Your console should display the following:Please enter the value of n: 10The sum of the last four numbers is 34Thank you. Before computing the difference of the numbers in the array, your code must performachecking; if n < 3, you should display a message ‘The value of n is less than 4’, and no operationwill be performed. In this case, your console should display the following:               Please enter the value of n: 1 The entered n is less than 3. Thank you                                                                                                                              Type the…

Chapter 4 Solutions

COMPUTER ORGANIZATION+DESIGN >I<

Ch. 4 - Prob. 4.4.2ECh. 4 - Prob. 4.4.3ECh. 4 - Prob. 4.4.4ECh. 4 - Prob. 4.4.5ECh. 4 - Prob. 4.4.6ECh. 4 - Prob. 4.5.1ECh. 4 - Prob. 4.5.2ECh. 4 - Prob. 4.6.1ECh. 4 - Prob. 4.6.2ECh. 4 - Prob. 4.6.3ECh. 4 - Prob. 4.6.4ECh. 4 - Prob. 4.6.5ECh. 4 - Prob. 4.7.1ECh. 4 - Prob. 4.7.2ECh. 4 - Prob. 4.7.3ECh. 4 - Prob. 4.7.4ECh. 4 - Prob. 4.7.5ECh. 4 - Prob. 4.7.6ECh. 4 - Prob. 4.8.1ECh. 4 - Prob. 4.8.2ECh. 4 - Prob. 4.8.3ECh. 4 - Prob. 4.8.4ECh. 4 - Prob. 4.8.5ECh. 4 - Prob. 4.8.6ECh. 4 - Prob. 4.9.1ECh. 4 - Prob. 4.9.2ECh. 4 - Prob. 4.9.3ECh. 4 - Prob. 4.9.4ECh. 4 - Prob. 4.9.5ECh. 4 - Prob. 4.9.6ECh. 4 - Prob. 4.10.1ECh. 4 - Prob. 4.10.2ECh. 4 - Prob. 4.10.3ECh. 4 - Prob. 4.10.4ECh. 4 - Prob. 4.10.5ECh. 4 - Prob. 4.10.6ECh. 4 - Prob. 4.11.1ECh. 4 - Prob. 4.11.2ECh. 4 - Prob. 4.12.1ECh. 4 - Prob. 4.12.2ECh. 4 - Prob. 4.12.3ECh. 4 - Prob. 4.12.4ECh. 4 - Prob. 4.12.5ECh. 4 - Prob. 4.12.6ECh. 4 - Prob. 4.13.1ECh. 4 - Prob. 4.13.2ECh. 4 - Prob. 4.13.3ECh. 4 - Prob. 4.13.4ECh. 4 - Prob. 4.13.5ECh. 4 - Prob. 4.13.6ECh. 4 - Prob. 4.14.1ECh. 4 - Prob. 4.14.2ECh. 4 - Prob. 4.14.3ECh. 4 - Prob. 4.14.4ECh. 4 - Prob. 4.14.5ECh. 4 - Prob. 4.14.6ECh. 4 - Prob. 4.15.1ECh. 4 - Prob. 4.15.2ECh. 4 - Prob. 4.15.3ECh. 4 - Prob. 4.15.4ECh. 4 - Prob. 4.15.5ECh. 4 - Prob. 4.15.6ECh. 4 - Prob. 4.16.1ECh. 4 - Prob. 4.16.2ECh. 4 - Prob. 4.16.3ECh. 4 - Prob. 4.16.4ECh. 4 - Prob. 4.16.5ECh. 4 - Prob. 4.16.6ECh. 4 - Prob. 4.17.1ECh. 4 - Prob. 4.17.2ECh. 4 - Prob. 4.17.3ECh. 4 - Prob. 4.17.4ECh. 4 - Prob. 4.17.5ECh. 4 - Prob. 4.18.1ECh. 4 - Prob. 4.18.2ECh. 4 - Prob. 4.18.3ECh. 4 - Prob. 4.18.4ECh. 4 - Prob. 4.18.5ECh. 4 - Prob. 4.18.6ECh. 4 - Prob. 4.19.1ECh. 4 - Prob. 4.19.2ECh. 4 - Prob. 4.19.3ECh. 4 - Prob. 4.19.4ECh. 4 - Prob. 4.19.5ECh. 4 - Prob. 4.19.6E
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