The number of grains of Aspirin present in one tablet should be calculated by using given of NaOH solution. Concept introduction: Precipitation reaction: If precipitate is formed, when two soluble salt solutions are mixed together is known as precipitation reaction. The mass of precipitate is depends on the reactant masses. Molarity: The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution. Molarity = No .mole volume (L) Mole: The mole of compound is given by the ratio between taken mass of the compound and molar mass of the compound. Mole = Massof the compound Molar mass of the compound Mole: The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is, Mole = Concentration (M)× volume (L)
The number of grains of Aspirin present in one tablet should be calculated by using given of NaOH solution. Concept introduction: Precipitation reaction: If precipitate is formed, when two soluble salt solutions are mixed together is known as precipitation reaction. The mass of precipitate is depends on the reactant masses. Molarity: The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution. Molarity = No .mole volume (L) Mole: The mole of compound is given by the ratio between taken mass of the compound and molar mass of the compound. Mole = Massof the compound Molar mass of the compound Mole: The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is, Mole = Concentration (M)× volume (L)
Solution Summary: The author explains that the number of grains of Aspirin present in one tablet should be calculated by using given of NaOH solution.
The number of grains of Aspirin present in one tablet should be calculated by using given of NaOH solution.
Concept introduction:
Precipitation reaction:
If precipitate is formed, when two soluble salt solutions are mixed together is known as precipitation reaction.
The mass of precipitate is depends on the reactant masses.
Molarity:
The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.
Molarity=No.molevolume(L)
Mole:
The mole of compound is given by the ratio between taken mass of the compound and molar mass of the compound.
Mole=MassofthecompoundMolarmassofthecompound
Mole:
The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,
3. Two solutions are prepared using the same solute:
Solution A: 0.14 g of the solute dissolves in 15.4 g of t-butanol
Solution B: 0.17 g of the solute dissolves in 12.7 g of cyclohexane
Which solution has the greatest freezing point change? Show calculations and explain.
2. Give the ground state electron configuration (e.g., 02s² σ*2s² П 2p²) for these molecules and deduce
its bond order.
Ground State Configuration
Bond Order
H2+
02-
N2
1. This experiment is more about understanding the colligative properties of a solution rather than the determination of
the molar mass of a solid.
a. Define colligative properties.
b. Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water?
Explain.
(i) 0.01 mol of CaCl2
(ii) 0.01 mol of KNO3
(iii) 0.01 mol of CO(NH2)2
(an electrolyte)
(an electrolyte)
(a nonelectrolyte)
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