Chapter 4, Problem 4.13NP

Interpretation Introduction

Interpretation:

The standard enthalpy ${\text{ΔH}}_{\text{R}}^{\text{0}}$ and standard internal energy change ${\text{ΔU}}_{\text{R}}^{\text{0}}$ associated with the oxidation of benzene needs to be calculated

Concept Introduction:

The standard enthalpy change for a reaction ${\text{ΔH}}_{\text{R}}^{\text{0}}$ is given in terms of the difference in the standard enthalpy of formation of the products and that of reactants.

  ${\text{ΔH}}_{\text{R}}^{\text{0}}\text{ = }{\displaystyle \sum {\text{n}}_{\text{p}}{\text{ΔH}}_{\text{f}}^{\text{0}}}\text{(products) - }{\displaystyle \sum {\text{n}}_{\text{r}}{\text{ΔH}}_{\text{f}}^{\text{0}}}\text{(reactants) ------(1)}$

For a given chemical reaction, ${\text{ΔH}}_{\text{R}}^{\text{0}}$ and ${\text{ΔU}}_{\text{R}}^{\text{0}}$ are related by the following equation:

  ${\text{ΔH}}_{\text{R}}^{\text{0}}{\text{ = ΔU}}_{\text{R}}^{\text{0}}\text{+ ΔnRT -----(2)}$

Here, Δn = change in the number of moles

R = gas constant; T = temperature