Chapter 4, Problem 4.12NP

(a)

Interpretation Introduction

Interpretation:

The standard enthalpy of the reaction corresponding to the formation of TiCl4(l) at a temperature of 135.8°C needs to be deduced

Concept Introduction:

The enthalpy of reaction at temperature T is related to the standard enthalpy of reaction at 298 K by the following equation:

  $\begin{array}{l}{\text{ΔH}}_{\text{R}}^{\text{0}}{\text{(T) = ΔH}}_{\text{R}}^{\text{0}}\text{(298K) + }{\displaystyle \underset{\text{298}}{\overset{\text{T}}{\int }}{\text{ΔC}}_{\text{p}}}\text{dT ------(1)}\\ {\text{where ΔC}}_{\text{p}}={\displaystyle \sum {\text{C}}_{\text{p}}}\text{(products)}-{\displaystyle \sum {\text{C}}_{\text{p}}}\text{(reactants) i}\text{.e}\text{. the difference in the heat}\\ \text{capacities of the products and reactants}\end{array}$

(b)

Interpretation Introduction

Interpretation:

The standard enthalpy of formation of TiCl₄(l) at a temperature of 25°C needs to be deduced

Concept Introduction:

The standard enthalpy change for a reaction ${\text{ΔH}}^{\text{0}}$ is given in terms of the difference in the standard enthalpy of formation of the products and that of reactants.

i.e. $\Delta {\text{H}}^0\text{ = }{\displaystyle \sum {\text{n}}_{\text{p}}{\text{ΔH}}_{\text{f}}^{\text{0}}}\text{(products) - }{\displaystyle \sum {\text{n}}_{\text{r}}{\text{ΔH}}_{\text{f}}^{\text{0}}}\text{(reactants) ------(2)}$

Here, n_p and n_r are the number of moles of the products and reactants