The mass percentage of Mg in a magnesium-aluminium alloy that has a mass of 0.263 g is to be determined. Concept introduction: Mass percent is employed to determine the concentration of one compound in a mixture of the compound. The formula to calculate mass percent is as follows: Mass percent of compound = ( mass of the compound mass of mixture )
The mass percentage of Mg in a magnesium-aluminium alloy that has a mass of 0.263 g is to be determined. Concept introduction: Mass percent is employed to determine the concentration of one compound in a mixture of the compound. The formula to calculate mass percent is as follows: Mass percent of compound = ( mass of the compound mass of mixture )
The mass percentage of Mg in a magnesium-aluminium alloy that has a mass of 0.263 g is to be determined.
Concept introduction:
Mass percent is employed to determine the concentration of one compound in a mixture of the compound. The formula to calculate mass percent is as follows:
Mass percent of compound=(mass of the compoundmass of mixture)
(b)
Interpretation Introduction
Interpretation:
The mass percentage of Mg in a magnesium-aluminium alloy that reacts with excess aqueous HCl and forms 1.38×10−2molH2 is to be determined.
Concept introduction:
Stoichiometry of a reaction is utilized to determine the amount of any species in the reaction by the relationship between the reactants and products.
Consider the general reaction,
A+2B→3C
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.
(c)
Interpretation Introduction
Interpretation:
The mass percentage of Mg in a magnesium-aluminium alloy that reacts with excess O2 and forms 0.483g of oxide is to be determined.
Concept introduction:
Stoichiometry of a reaction is utilized to determine the amount of any species in the reaction by the relationship between the reactants and products.
Consider the general reaction,
A+2B→3C
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3 and the stoichiometric ratio between B and C is 2:3.
Draw the monomers required to synthesize this condensation polymer.
Draw the monomers required to synthesize this condensation polymer.
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O Measurement and Matter
=1
Setting up a unit conversion
110
Eddie says...
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A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.
(-
4
J
kJ
-7.0 × 10
☐ = ?
mmol.°C
mol °C
x10
μ
Explanation
Check
□·□
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