Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 4, Problem 4.12P
To determine
Find the shrinkage limit of the soil.
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Following are the results of a shrinkage limit test:
Initial volume of soil in saturated state = 29.60 cc
Final volume of soil in a dry state = 19.90 cc
Initial mass in a saturated state = 50 g
Final mass in a dry state = 33 g
Determine the shrinkage limit of the soil.
PROBLEM No. 5
Shrinkage Limit
Following are the results of a shrinkage limit test:
= 26 cm3
19 cm3
Initial volume of soil in saturated state =
Final volume of soil in a dry state
46 g
Initial mass in a saturated state =
Final mass in a dry state = 32 g
Determine the shrinkage limit of the soil
Determine the shrinkage ratio
Determine the specific gravity of the solids
d. If the soil at natural state has a moisture content of 25%,
estimate the maximum volumetric shrinkage.
Estimate the linear shrinkage.
а.
b.
С.
е.
Chapter 4 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 4 - During Atterberg limit tests in the soil mechanics...Ch. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Results from a liquid limit test conducted on a...Ch. 4 - The following data were obtained by conducting...Ch. 4 - Refer to the soil in Problem 4.5. Using the...Ch. 4 - Following results are obtained for a liquid limit...Ch. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10P
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- A SOIL SAMPLE WAS TAKEN FROM A SITE AND WAS PLACED IN A CUBICAL CONTAINER WITH ONE SIDE EQUAL TO 0.1m. THE NET WEIGHT OF THE SOIL IS FOUND OUT TO BE 2kN. AFTER OVEN DRYING, THE WEIGHT WAS REDUCED TO 53%. WHAT IS THE UNIT WEIGHT OF THE SOIL AFTER DRYING? * Your answer A SATURATED SOIL HAS VOID RATIO EQUAL TO 0.65 AND sg = 2.9. WHAT IS THE SUBMERGED UNIT WEIGHT OF THE SOIL? * Your answer THE WEIGHT OF THE VOIDS OF ON SITE SOIL WAS MEASURED AND FOUND OUT TO BE 1 kN. AFTER DRYING, THE WEIGHT OF THE SOLID WAS FOUND TO BE 1 kN. IF THE VOLUME OF THE SOIL IS 0.099 m3, WHAT IS THE NATURAL UNIT WEIGHT OF THE SOIL? * Your answerarrow_forwardPROBLEM No. 5 Following are the results of a shrinkage limit test: 26.4 cm3 Final volume of soil in a dry state = 19.5 cm³ 45.6 g Initial volume of soil in saturated state = Initial mass in a saturated state = Final mass in a dry state 31.5 g Determine the shrinkage limit of the soil Describe the quality of the soil based on the shrinkage а. b. limit. Determine the shrinkage ratio d. Determine the specific gravity of the solids If the soil at natural state has a moisture content of 30%, estimate the maximum volumetric shrinkage. Estimate the linear shrinkage. С. е. f.arrow_forwardExample 2.21:The liquid limit and plastic limit of a soil are 50 % and 25 %, respectively When the soil was dried from its state at liquid limit, the decrease in volume was 40 pe cent of the volume at liquid limit. When it was dried from its state at plastic limit, the volume decrease was 20 per cent of the volume at plastic limit. Determine the shrinkag limit and shrinkage ratio.arrow_forward
- A saturated 100 cm^3 clay sample has a natural water content of 30%. It is found that the shrinkage limit occurs when the water content is 19%. The specific gravity of the soil is 2.70. a. What is the initial mass of the soil in grams? b. What is the dry mass of the soil in grams? c. What is the final volume of the soil in cm^3 after drying? d. What is the volume of the sample in cm^3 when the water content is 15%?arrow_forwardSituation 3 - Following are the results of a shrinkage limit test: Initial volume of soil in saturated state 25.7 cm3 Final volume of soil in dry state 19.6 cm3 Initial mass in saturated state 47.0 g Final mass in dry state 33.0 g Determine the shrinkage ratio of the soil. Round off to two decimal places.arrow_forwardThe consistency limits of a given soil are LL=60%, PL= 45 % and SL= 25% . The specific gravity of the soil solids is 2.67. A sample of this soil at liquid has a volume of 20 cc. What will be its final volume in cm3 if the sample is brought to its shrinkage limit? a.2.67 b.7.18 c.12.82 d.1.602arrow_forward
- 8. A sample of soil has a water content w= 14.7%, and a cube of dimensions 10 cm x 10 cm × 10 cm weighs 18.4 N. The grain specific gravity Gs = 2.72. Calculate the unit weight, the void ratio and the degree of saturation. What would be the unit weight and the water content if the soil had the same void ratio, but was saturated? What would be the unit weight if the soil had a water content of zero?arrow_forward. A shrinkage limit test on a clay soil gave the following data. Compute the shrinkage limit. Assuming that the total volume of dry soil cake is equal to its total volume at the shrinkage limit, what is the degree of shrinkage? Comment on the nature of soil. Mass of shrinkage dish and saturated soil M1 = 38.78 g Mass of shrinkage dish and oven dry soil M2 = 30.46 g Mass of shrinkage dish M3 = 10.65 g Volume of shrinkage dish Vo = 16.29 cm3 Total volume of oven dry soil cake Vd = 10.00 cm3arrow_forwardFollowing are the results of a shrinkage limit test: Initial volume of soil in a saturated state = 26.6 cm3 Final volume of soil in a dry state = 15.9 cm3 Initial mass of soil in a saturated state = 44 g Initial mass of soil in a dry state = 30.1 g Gs = 2.70 1. Shrinkage limit of the soil 2. Saturated unit weight if e = 30.1 g 3. Dry unit weightarrow_forward
- on 1: Determine the shrinkage ratio of the soil. Calculate the specific gravity of soil solids. Following are the results of a shrinkage limit test: Initial volume of soil in a saturated state = 24.6 cm³ Final volume of soil in a dry state = 15.9 cm³ Initial mass in a saturated state = 44.0 g Final mass in a dry state = 30.1 garrow_forwardFollowing are the results of a shrinkage limit test. Determin the shrinkage limit, in percent, of the soil. Round off to two decimal places.arrow_forwardProblem H During the determination of the shrinkage limit of a sandy clay, the following laboratory data was obtained. Wet weight of soil + dish Dry weight of soil + dish Weight of dish = 86.55 g = 75.51 g = 51.60 g Volumetric determination of soil pat: Weight of dish + mercury Weight of dish = 431.80 g = 242.62 g = 2640 kg/cu.m Density of a solid soil a. Compute the shrinkage limit of the soil. b. Compute the shrinkage ratio. c. Compute the specific gravity of soil.arrow_forward
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