
Concept explainers
Explanation of Solution
The following code is multiply two positive numbers with variables “X” and “Y”.
The hexadecimal address starts with “100” in instruction.
100 Load Y/Load the Second value
101 Store Temp/Store the second value in temporary /variable
102 Loop, Load Result/Load the Result
103 Add X/Add X to the Result
104 Store Result/Store the final value in Result
105 Load Temp/Load the Temp
106 Subt One/Decrement the counter
107 Store Temp/Store the temporary value
108 SkipCond 400/If AC=0, discontinue loop
109 Jump Loop/If AC is not 0, continue loop
10A Endloop, Load Result /End the loop
10B Output/Print the result
10C Halt/terminate the p...

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Chapter 4 Solutions
Essentials of Computer Organization and Architecture
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