Chapter 4, Problem 10E

a)

Explanation of Solution

Required number of RAM chips:

From given scenario, the $\text{2M×16}$ bits can converted into ${\text{2}}^{\text{21}}{\text{×2}}^{\text{4}}\text{ bytes}$ and $\text{256K×8}$ can converted into ${\text{2}}^{\text{18}}{\text{×2}}^3\text{ bytes}$.

The required number of RAM chips is $\frac{\text{2M×16}}{\text{256K×8}}\text{ =�}$

b)

Explanation of Solution

Number of involved chips:

The number of involved chips is “two”. Because, the memory has 16-bit word...

c)

Explanation of Solution

Number of address bits needed for each RAM chip:

From given $\text{256K×8}$ RAM chips, the number of needed address bits is calculated as ${}^{}$

d)

Explanation of Solution

Number of banks in given memory:

The number of banks is calculated using the addressable item in each main memory and the RAM chips.

$\begin{array}{c}\text{Number of banks = }\frac{\text{2M}}{\text{256K}}\\ \text{= }\frac{{}^{}}{}\end{array}$

e)

Explanation of Solution

Number of needed address bits:

The main memory have 2M in addressable item. So, the number of needed bits for all the memory is ${\text{2M = 2}}^{}$

f)

Program Plan Intro

High-order interleaving:

It is the type of memory interleaving which splits the memory into various banks. The higher order of bits are used to access the banks in memory.

g)

Program Plan Intro

Low-order interleaving:

It is the type of memory interleaving which splits the memory into various banks. The low order of bits are used to access the banks in memory.