UNIVERSE (LOOSELEAF):STARS+GALAXIES
6th Edition
ISBN: 9781319115043
Author: Freedman
Publisher: MAC HIGHER
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Chapter 4, Problem 26Q
To determine
(a)
The semi major axis of the comet’s orbit.
To determine
(b)
The perihelion distance, if aphelion distance is 31.5AU.
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Chapter 4 Solutions
UNIVERSE (LOOSELEAF):STARS+GALAXIES
Ch. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4QCh. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10Q
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- What is the average distance from the Sun (in astronomical units) of a planet with an orbital period of 45.66 years?arrow_forwardEros has an elliptical orbit about the Sun, with a perihelion distance of 1.13 AU and aphelion distance of 1.78 AU. What is the period of its orbit?arrow_forwardIf a planet has an average distance from the Sun of 2.0 AU, what is its orbital period?arrow_forward
- Must engineers take Earth’s rotation into account when constructing very tall buildings at any location other than the equator or very near the poles?arrow_forwardConsider an imaginary planet in our solar system at an average distance of25 AU from the Sun.(a) Calculate the orbital period of this planet. (b) This fictional planet has an orbital eccentricity of e = 0.4, calculatethe planet’s distance to the Sun at aphelion and perihelion. (c) Another imaginary planet in our solar system has a perihelion distanceof 12 AU from the Sun and an aphelion distance of 68 AU. Is theeccentricity of this new planet greater or less than the planet in theprevious question?arrow_forwardAccording to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 x 105 km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). a) Calculate the orbital velocity of the Moon. b) Calculate mass of the Earth.arrow_forward
- According to Lunar Laser Ranging experiments the average distance L M from the Earth to the Moon is approximately 3.85 × 105 km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). Calculate mass of the Eartharrow_forwardPluto’s orbit around the Sun is highly elliptical compared to the planets in our Solar System. It has a perihelion distance of 29.7 AU and an aphelion distance of 49.5 AU. a) What is the semi-major axis of Pluto’s orbit, in AU? b) What is Pluto’s orbital period, in Earth years?arrow_forwardThe average Earth-Moon distance is 3.84 X 10^5 km, while the Earth-Sun is 1.496 X 10^8 km. Since the radius of the Moon is 1.74 X 10^3 km and that of the Sun is 6.96 X 10^5 km. a) Calculate the angular radius of the Moon and the Sun, qmax, according to the following figure. D Bax R b) Calculate the solid angle of the Moon and the Sun as seen from Earth. (c) Interpret its results; Would this be enough to explain the occurrence of total solar eclipses?arrow_forward
- Calculate the altitude needed for a circular, geosynchronous orbit (an orbit whose orbital period matches Earth’s rotation rate, with a period equal to a sidereal day, 23hrs 56min).arrow_forward(a) Jupiter's third-largest natural satellite, Io, follows an orbit with a semimajor axis of 422,000 km (4.22 ✕ 105 km) and a period of 1.77 Earth days (PIo = 1.77 d). To use Kepler's Third Law, we first must convert Io's orbital semimajor axis to astronomical units. One AU equals 150 million km (1 AU = 1.50 ✕ 108 km). Convert Io's a value to AU and record the result. aIo = AU (b) One Earth year is about 365 days. Convert Io's orbital period to Earth years and record the result. PIo = yr (c) Use the Kepler's Third Law Calculator to calculate Jupiter's mass in solar units. Record the result. MJup(Io) = MSun (d) Based on this result, Jupiter's mass is about that of the Sun. Jupiter has a similar fraction of the Sun's volume. The two objects therefore have rather similar density! In fact, Jupiter has a fairly similar composition as well: most of its mass is in the form of hydrogen and helium.arrow_forwardObservations and trigonometry can be used to determine that Earth's moon has an orbital period of 27.32 days and a mean orbital radius of 384,400 km. Using this information, calculate the mass of the Earth.arrow_forward
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