EBK CONCEPTS OF PROGRAMMING LANGUAGES
12th Edition
ISBN: 9780135102251
Author: Sebesta
Publisher: VST
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Chapter 4, Problem 25RQ
Explanation of Solution
Purpose of the ACTION table of an LR parser:
LR parser is a table driven parser and the table has two components- ACTION table and GOTO table.
- As the name specifies, ACTION part specifies the actions required to taken by the parser. It specifies what a parser should do.
- Rows of the ACTION table are labeled with states and columns are labeled with terminal symbols in the grammar.
- The main actions specified in the table are Shift or Reduce. That is, either the parser can shift the next input symbol to the stack or it can reduce the handle on the top of the stack to its corresponding LHS...
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Test if the following schedule is conflict serializable or not and explain
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Test if the following schedule is conflict serializable or not and explain
R1 (A), R2 (D), W1 (B), R2 (B), W3 (B), R4 (B), W2 (C), R5 (C), W4 (E), R5 (E), W5 (B).
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a. What is lossy decomposition? Check whether the following decompositions are lossy or lossless.
(i) Let R=ABCD, R1 = AD, R2 = AB, R3 = BE, R4 = CDE, R5 = AE, F={ A->C, B- >C, C->D, DE->C, CE->A}
(ii) R (XYZWQ), FD= {X->Z, Y->Z, Z->W, WQ->Z, ZQ-> X, R1 (XW), R2 (XY), R3 (YQ) , R4 (ZWQ), R5 (XQ)
b. Eliminate redundant FDs from
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Chapter 4 Solutions
EBK CONCEPTS OF PROGRAMMING LANGUAGES
Ch. 4 - Prob. 1RQCh. 4 - Prob. 2RQCh. 4 - Prob. 3RQCh. 4 - Prob. 4RQCh. 4 - Prob. 5RQCh. 4 - Prob. 6RQCh. 4 - Prob. 7RQCh. 4 - Prob. 8RQCh. 4 - Prob. 9RQCh. 4 - Prob. 10RQ
Ch. 4 - Prob. 11RQCh. 4 - Prob. 12RQCh. 4 - Prob. 13RQCh. 4 - Prob. 14RQCh. 4 - Prob. 15RQCh. 4 - Prob. 16RQCh. 4 - Prob. 17RQCh. 4 - Prob. 18RQCh. 4 - Prob. 19RQCh. 4 - Prob. 20RQCh. 4 - Prob. 21RQCh. 4 - Prob. 22RQCh. 4 - Prob. 23RQCh. 4 - What was Knuths insight in developing the LR...Ch. 4 - Prob. 25RQCh. 4 - Prob. 26RQCh. 4 - Is left recursion a problem for LR parsers?Ch. 4 - Prob. 1PSCh. 4 - Prob. 2PSCh. 4 - Prob. 3PSCh. 4 - Prob. 4PSCh. 4 - Prob. 7PSCh. 4 - Prob. 8PS
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