Find the apportionment under Jefferson’s method of the Wadiya Congress described in Exercise 2 . ( Hint : Look for suitable divisors in the interval 49,400 to 49,600) 2. The Republic of Wadiya is a small country consisting of four provinces: A (population 4,360,000), B (population 2,280,000), C (population 729,000), and D (population 2,631,000). Suppose that there are M = 200 seats in the Wadiya Congress, to be apportioned among the four provinces based on their respective populations.
Find the apportionment under Jefferson’s method of the Wadiya Congress described in Exercise 2 . ( Hint : Look for suitable divisors in the interval 49,400 to 49,600) 2. The Republic of Wadiya is a small country consisting of four provinces: A (population 4,360,000), B (population 2,280,000), C (population 729,000), and D (population 2,631,000). Suppose that there are M = 200 seats in the Wadiya Congress, to be apportioned among the four provinces based on their respective populations.
Find the apportionment under Jefferson’s method of the Wadiya Congress described in Exercise 2. (Hint: Look for suitable divisors in the interval 49,400 to 49,600)
2. The Republic of Wadiya is a small country consisting of four provinces: A (population 4,360,000), B (population 2,280,000), C (population 729,000), and D (population 2,631,000). Suppose that there are M = 200 seats in the Wadiya Congress, to be apportioned among the four provinces based on their respective populations.
1 2
21. For the matrix A
=
3 4
find AT (the transpose of A).
22. Determine whether the vector
@
1
3
2
is perpendicular to
-6
3
2
23. If v1
=
(2)
3
and v2 =
compute V1 V2 (dot product).
.
7. Find the eigenvalues of the matrix
(69)
8. Determine whether the vector
(£)
23
is in the span of the vectors
-0-0
and
2
2
1. Solve for x:
2. Simplify:
2x+5=15.
(x+3)² − (x − 2)².
-
b
3. If a = 3 and 6 = 4, find (a + b)² − (a² + b²).
4. Solve for x in 3x² - 12 = 0.
-
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