MATLAB: An Introduction with Applications
5th Edition
ISBN: 9781118629864
Author: Amos Gilat
Publisher: WILEY
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Chapter 4, Problem 21P
To determine
The coordinates of the center and radius of the circle passing through three given points.
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Solve the following systems using Gauss Seidal and Jacobi iteration
methods for n=8 and initial values X0=(000).
-
2x16x2 x3 = -38
-
-3x1 x2+7x3 = −34
-8x1 + x2 - 2x3
= -20
Solve the following systems using Gauss Seidal and Jacobi iteration
methods for n=8 and initial values Xº=(000).
3x12x2x3 = 4
-
2x1 x2 + 2x3 = 10
x13x24x3 = 4
Use Newton-Raphson method to solve the system
x²
-
2x-y+0.5= 0
x² + 4y² 4 = 0
-
with the starting value (xo,yo) = (2,0.25) and two iteration number.
Chapter 4 Solutions
MATLAB: An Introduction with Applications
Ch. 4 - Prob. 1PCh. 4 - The monthly saving P that has to be deposit in a...Ch. 4 - Prob. 3PCh. 4 - The volume V and the surface area S of a...Ch. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 -
7. A rocket flying straight up measures the...Ch. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - The balance of a loan, B, after n monthly payments...
Ch. 4 - Early explorers often estimated altitude by...Ch. 4 - An isosceles triangle sign is designed to have a...Ch. 4 - 13. A round billboard with radius R — 55 in. is...Ch. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - The intrinsic electrical conductivity a of a...Ch. 4 - Prob. 19PCh. 4 - The net heat exchange by radiation from plate 1...Ch. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - The surface of many airfoils can be described with...Ch. 4 - During a golf match, a certain number of points...Ch. 4 - The dissolution of copper sulfide in aqueous...Ch. 4 - 28. The wind chill temperature, 7WC, is the air...Ch. 4 - Prob. 29P
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- Solve the following systems using Gauss Seidal and Jacobi iteration methods for n=8 and initial values X0=(000). - 2x16x2 x3 = -38 - -3x1 x2+7x3 = −34 -8x1 + x2 - 2x3 = -20arrow_forwardSolve the following nonlinear system using Newton's method 1 f1(x1, x2, x3)=3x₁ = cos(x2x3) - - 2 f2(x1, x2, x3) = x² - 81(x2 +0.1)² + sin x3 + 1.06 f3(x1, x2, x3) = ex1x2 +20x3 + Using x (0) X1 X2 X3 10π-3 3 = 0.1, 0.1, 0.1 as initial conditioarrow_forwardA single phase a.c. distributor AB has: The distance from A to B is 500 m. The distance from A to C is 800 m. The impedance of each section is (6+j 8) /km. A B C The voltage at the far end is maintained at 250 volt. Find: sending voltage, sending current, supply power factor and 80 A 60 A total voltage drop. 0.8 lag. P.f 0.6 lead. p.farrow_forward
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