MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
5th Edition
ISBN: 9781118629864
Author: Amos Gilat
Publisher: WILEY
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Chapter 1, Problem 1P
To determine

(a)

To solve:

The equation 22+5.12506.32.

Expert Solution
Check Mark

Answer to Problem 1P

Solution:

The value of the equation 22+5.12506.32 is 4.6566.

Explanation of Solution

Solve the given equation.

22+5.12506.3248.0110.314.6566

Write the MATLAB script that calculates the equation 22+5.12506.32.

MATLAB Code:

(22+5.1^2)/(50-6.3^2)

% Calculate the value of the equation

Save the MATLAB script with name, Chapter1_29864_1_1Pa.min the current folder. Execute the script by typing the script name at the command window to get the answer for 22+5.12506.32.

Result:

MATLAB: An Introduction with Applications, Chapter 1, Problem 1P , additional homework tip  1

Conclusion:

Therefore, the value of the equation 22+5.12506.32 is 4.6566.

To determine

(b)

To solve:

The equation 447+825993.92.

Expert Solution
Check Mark

Answer to Problem 1P

Solution:

The value of the equation 447+825993.92 is 12.5768.

Explanation of Solution

Solve the given equation.

447+825993.926.2857+12.86.508912.5768

Write the MATLAB script that calculates the equation 447+825993.92.

MATLAB Code:

44/7+8^2/5-99/3.9^2

% Calculate the value of the equation

Save the MATLAB script with name, Chapter1_29864_1_1Pb.min the current folder. Execute the script by typing the script name at the command window to get the answer for 447+825993.92.

Result:

MATLAB: An Introduction with Applications, Chapter 1, Problem 1P , additional homework tip  2

Conclusion:

Therefore, the value of the equation 447+825993.92 is 12.5768.

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Chapter 1 Solutions

MATLAB: An Introduction with Applications

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