Explanation Calculation: Consider the given information: The parabolic archway is 16 meters high from the vertex. At a height of 14 meters, the width of the archway is 12 meters. The figure of the given parabola is, According to the above figure, the equation for the parabola is x 2 = 4 p y − 16 The points on the graph are − 6 , − 14 , 0 , 16 and 6 , 14 . Now, substitute the value of x = 6 and y = 14 as, 6 2 = 4 p 14 − 16 37 = 4 p 14 − 16 − 9 2 = p Hence, the value of p is − 9 2

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Author: Ron Larson

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Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.

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Chapter 4, Problem 20T

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To calculate: The width of the archway at the ground level, if the parabolic archway is 16 meters high from the vertex. At a height of 14 meters, the width of the archway is 12 meters.

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Chapter 4, Problem 19T

Chapter 4, Problem 21T

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The width of the archway at the ground level, if the parabolic archway is 16 meters high from the vertex. At a height of 14 meters, the width of the archway is 12 meters.

Solution Summary: The author calculates the width of the parabolic archway at the ground level, if it is 16 meters high from the vertex.

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To calculate: The width of the archway at the ground level, if the parabolic archway is 16 meters high from the vertex. At a height of 14 meters, the width of the archway is 12 meters.

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