Integrated Science
Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 4, Problem 1PEA
To determine

The equivalent temperature on the Celsius Scale.

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L₁ D₁ L₂ D2 Aluminum has a resistivity of p = 2.65 × 10 8 2. m. An aluminum wire is L = 2.00 m long and has a circular cross section that is not constant. The diameter of the wire is D₁ = 0.17 mm for a length of L₁ = 0.500 m and a diameter of D2 = 0.24 mm for the rest of the length. a) What is the resistance of this wire? R = Hint A potential difference of AV = 1.40 V is applied across the wire. b) What is the magnitude of the current density in the thin part of the wire? Hint J1 = c) What is the magnitude of the current density in the thick part of the wire? J₂ = d) What is the magnitude of the electric field in the thin part of the wire? E1 = Hint e) What is the magnitude of the electric field in the thick part of the wire? E2 =
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A cheetah spots a gazelle in the distance and begins to sprint from rest, accelerating uniformly at a rate of 8.00 m/s^2 for 5 seconds. After 5 seconds, the cheetah sees that the gazelle has escaped to safety, so it begins to decelerate uniformly at 6.00 m/s^2 until it comes to a stop.
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