The println statement in the given program segment displays the value “ 5 ”. Hence, the correct answer is option “ A ”.

Question

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Answer 1

Expert Solution & Answer

Chapter 4, Problem 1MC

Program Description Answer

The println statement in the given program segment displays the value “5”.

Hence, the correct answer is option “A”.

Expert Solution & Answer

Explanation of Solution

Increment operator “++”:

The increment operator is used to increment or increase the value of the variable by “1”.

Example:

/*the variable val is increased by 1 with a postfix representation */

val++;

/*the variable val is increased by 1 with a prefix representation */

++val;

In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.

Explanation for incorrect options:

b. 6:

The value of “x” is incremented to 6 after it is displayed.

Hence, the option “B” is wrong.

c. 0:

The value of “x” is initialized as 5, and then it is not modified as “0”.

Hence, the option “C” is wrong.

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Answer 2

Expert Solution & Answer

Chapter 4, Problem 1MC

Program Description Answer

The println statement in the given program segment displays the value “5”.

Hence, the correct answer is option “A”.

Expert Solution & Answer

Explanation of Solution

Increment operator “++”:

The increment operator is used to increment or increase the value of the variable by “1”.

Example:

/*the variable val is increased by 1 with a postfix representation */

val++;

/*the variable val is increased by 1 with a prefix representation */

++val;

In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.

Explanation for incorrect options:

b. 6:

The value of “x” is incremented to 6 after it is displayed.

Hence, the option “B” is wrong.

c. 0:

The value of “x” is initialized as 5, and then it is not modified as “0”.

Hence, the option “C” is wrong.

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Answer 3

Expert Solution & Answer

Chapter 4, Problem 1MC

Program Description Answer

The println statement in the given program segment displays the value “5”.

Hence, the correct answer is option “A”.

Expert Solution & Answer

Explanation of Solution

Increment operator “++”:

The increment operator is used to increment or increase the value of the variable by “1”.

Example:

/*the variable val is increased by 1 with a postfix representation */

val++;

/*the variable val is increased by 1 with a prefix representation */

++val;

In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.

Explanation for incorrect options:

b. 6:

The value of “x” is incremented to 6 after it is displayed.

Hence, the option “B” is wrong.

c. 0:

The value of “x” is initialized as 5, and then it is not modified as “0”.

Hence, the option “C” is wrong.

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Answer 4

Expert Solution & Answer

Chapter 4, Problem 1MC

Program Description Answer

The println statement in the given program segment displays the value “5”.

Hence, the correct answer is option “A”.

Expert Solution & Answer

Explanation of Solution

Increment operator “++”:

The increment operator is used to increment or increase the value of the variable by “1”.

Example:

/*the variable val is increased by 1 with a postfix representation */

val++;

/*the variable val is increased by 1 with a prefix representation */

++val;

In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.

Explanation for incorrect options:

b. 6:

The value of “x” is incremented to 6 after it is displayed.

Hence, the option “B” is wrong.

c. 0:

The value of “x” is initialized as 5, and then it is not modified as “0”.

Hence, the option “C” is wrong.

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Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 4, Problem 1MC

Program Description Answer

The println statement in the given program segment displays the value “5”.

Hence, the correct answer is option “A”.

Expert Solution & Answer

Explanation of Solution

Increment operator “++”:

The increment operator is used to increment or increase the value of the variable by “1”.

Example:

/*the variable val is increased by 1 with a postfix representation */

val++;

/*the variable val is increased by 1 with a prefix representation */

++val;

In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.

Explanation for incorrect options:

b. 6:

The value of “x” is incremented to 6 after it is displayed.

Hence, the option “B” is wrong.

c. 0:

The value of “x” is initialized as 5, and then it is not modified as “0”.

Hence, the option “C” is wrong.

Answer 8

Chapter 4, Problem 1MC

Program Description Answer

The println statement in the given program segment displays the value “5”.

Hence, the correct answer is option “A”.

Expert Solution & Answer

Explanation of Solution

Increment operator “++”:

The increment operator is used to increment or increase the value of the variable by “1”.

Example:

/*the variable val is increased by 1 with a postfix representation */

val++;

/*the variable val is increased by 1 with a prefix representation */

++val;

In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.

Explanation for incorrect options:

b. 6:

The value of “x” is incremented to 6 after it is displayed.

Hence, the option “B” is wrong.

c. 0:

The value of “x” is initialized as 5, and then it is not modified as “0”.

Hence, the option “C” is wrong.

Answer 9

Chapter 4, Problem 1MC

Program Description Answer

The println statement in the given program segment displays the value “5”.

Hence, the correct answer is option “A”.

Answer 10

Expert Solution & Answer

Explanation of Solution

Increment operator “++”:

The increment operator is used to increment or increase the value of the variable by “1”.

Example:

/*the variable val is increased by 1 with a postfix representation */

val++;

/*the variable val is increased by 1 with a prefix representation */

++val;

In the given program segment, the variable “x” is declared and initialized with the value “5”. In the println statement, post-increment operation is performed using the statement “x++”. As per postfix mode, the value of the variable “x” is printed and then the value is incremented. Therefore, the value of “x”, which is “5” is printed using the println statement and then the value of “x” is incremented.

Explanation for incorrect options:

b. 6:

The value of “x” is incremented to 6 after it is displayed.

Hence, the option “B” is wrong.

c. 0:

The value of “x” is initialized as 5, and then it is not modified as “0”.

Hence, the option “C” is wrong.