EBK INTRODUCTORY CHEMISTRY
EBK INTRODUCTORY CHEMISTRY
8th Edition
ISBN: 9780134553153
Author: CORWIN
Publisher: PEARSON CO
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 4, Problem 19E
Interpretation Introduction

(a)

Interpretation:

The number of neutrons in an atom of the isotope 11H is to be calculated.

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 19E

The number of neutrons in an atom of the isotope 11H is 0.

Explanation of Solution

The mass number of the isotope, 11H is 1 and atomic number is also 1.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=11=0

Therefore, the number of neutrons in an atom of the isotope 11H is 0.

Conclusion

The number of neutrons in an atom of the isotope 11H is 0.

Interpretation Introduction

(b)

Interpretation:

The number of neutrons in an atom of the isotope 24He is to be calculated

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 19E

The number of neutrons in an atom of the isotope 24He is 2.

Explanation of Solution

The mass number of the isotope, 24He is 4 and atomic number is 2.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=42=2

Therefore, the number of neutrons in an atom of the isotope 24He is 2.

Conclusion

The number of neutrons in an atom of the isotope 24He is 2.

Interpretation Introduction

(c)

Interpretation:

The number of neutrons in an atom of the isotope 816O is to be calculated

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 19E

The number of neutrons in an atom of the isotope 816O is 8.

Explanation of Solution

The mass number of the isotope, 816O is 16 and atomic number is 8.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=168=8

Therefore, the number of neutrons in an atom of the isotope 816O is 8.

Conclusion

The number of neutrons in an atom of the isotope 816O is 8.

Interpretation Introduction

(d)

Interpretation:

The number of neutrons in an atom of the isotope 1020Ne is to be calculated

Concept introduction:

The atomic number of an atom is equal to the number of protons in an atom. Mass number or atomic mass of an atom can be calculated by taking the sum of atomic number and number of neutrons.

Expert Solution
Check Mark

Answer to Problem 19E

The number of neutrons in an atom of the isotope 1020Ne is 10.

Explanation of Solution

The mass number of the isotope, 1020Ne is 20 and atomic number is 10.

The number of neutrons is calculated by the formula shown below.

Numberofneutrons=MassnumberAtomicnumber

Substitute the values of mass number and atomic number in the above equation.

Numberofneutrons=2010=10

Therefore, the number of neutrons in an atom of the isotope 1020Ne is 10.

Conclusion

The number of neutrons in an atom of the isotope 1020Ne is 10.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Steps and explanation please
Steps and explanation please. Add how to solve or target similar problems.
Steps and explanation please. Add how to solve or target similar problems.

Chapter 4 Solutions

EBK INTRODUCTORY CHEMISTRY

Ch. 4 - Prob. 11CECh. 4 - Prob. 12CECh. 4 - Prob. 1KTCh. 4 - Prob. 2KTCh. 4 - Prob. 3KTCh. 4 - Prob. 4KTCh. 4 - Prob. 5KTCh. 4 - Prob. 6KTCh. 4 - Prob. 7KTCh. 4 - Prob. 8KTCh. 4 - Prob. 9KTCh. 4 - Prob. 10KTCh. 4 - Prob. 11KTCh. 4 - Prob. 12KTCh. 4 - Prob. 13KTCh. 4 - Prob. 14KTCh. 4 - Prob. 15KTCh. 4 - Prob. 16KTCh. 4 - Prob. 17KTCh. 4 - Prob. 18KTCh. 4 - Prob. 19KTCh. 4 - Prob. 20KTCh. 4 - Prob. 21KTCh. 4 - Prob. 22KTCh. 4 - Prob. 23KTCh. 4 - Prob. 24KTCh. 4 - Prob. 25KTCh. 4 - Prob. 1ECh. 4 - Prob. 2ECh. 4 - Prob. 3ECh. 4 - Prob. 4ECh. 4 - Prob. 5ECh. 4 - Prob. 6ECh. 4 - Prob. 7ECh. 4 - Prob. 8ECh. 4 - Prob. 9ECh. 4 - Prob. 10ECh. 4 - Prob. 11ECh. 4 - Prob. 12ECh. 4 - Prob. 13ECh. 4 - Prob. 14ECh. 4 - Prob. 15ECh. 4 - Prob. 16ECh. 4 - Prob. 17ECh. 4 - Prob. 18ECh. 4 - Prob. 19ECh. 4 - Prob. 20ECh. 4 - Prob. 21ECh. 4 - Prob. 22ECh. 4 - Prob. 23ECh. 4 - Prob. 24ECh. 4 - Prob. 25ECh. 4 - Prob. 26ECh. 4 - Prob. 27ECh. 4 - Prob. 28ECh. 4 - Prob. 29ECh. 4 - Prob. 30ECh. 4 - Prob. 31ECh. 4 - Prob. 32ECh. 4 - Prob. 33ECh. 4 - Prob. 34ECh. 4 - Prob. 35ECh. 4 - Prob. 36ECh. 4 - Prob. 37ECh. 4 - Prob. 38ECh. 4 - Prob. 39ECh. 4 - Prob. 40ECh. 4 - Prob. 41ECh. 4 - Prob. 42ECh. 4 - Prob. 43ECh. 4 - Prob. 44ECh. 4 - Prob. 45ECh. 4 - Prob. 46ECh. 4 - Prob. 47ECh. 4 - Prob. 48ECh. 4 - Prob. 49ECh. 4 - Prob. 50ECh. 4 - Prob. 51ECh. 4 - Prob. 52ECh. 4 - Prob. 53ECh. 4 - Prob. 54ECh. 4 - Prob. 55ECh. 4 - Prob. 56ECh. 4 - Prob. 57ECh. 4 - Prob. 58ECh. 4 - Prob. 59ECh. 4 - Prob. 60ECh. 4 - Prob. 61ECh. 4 - Prob. 62ECh. 4 - Prob. 63ECh. 4 - Prob. 64ECh. 4 - Prob. 65ECh. 4 - Prob. 66ECh. 4 - Prob. 67ECh. 4 - Prob. 68ECh. 4 - Prob. 69ECh. 4 - Prob. 70ECh. 4 - Prob. 71ECh. 4 - Prob. 72ECh. 4 - Prob. 73ECh. 4 - Prob. 74ECh. 4 - Prob. 75ECh. 4 - Prob. 76ECh. 4 - Prob. 77ECh. 4 - Prob. 78ECh. 4 - Prob. 79ECh. 4 - Prob. 80ECh. 4 - Prob. 81ECh. 4 - Prob. 82ECh. 4 - Prob. 83ECh. 4 - Prob. 84ECh. 4 - Prob. 85ECh. 4 - Prob. 86ECh. 4 - Prob. 87ECh. 4 - Prob. 88ECh. 4 - Prob. 89ECh. 4 - Prob. 90ECh. 4 - Prob. 91ECh. 4 - Prob. 92ECh. 4 - Prob. 93ECh. 4 - Prob. 94ECh. 4 - Prob. 95ECh. 4 - Prob. 96ECh. 4 - Prob. 97ECh. 4 - Prob. 98ECh. 4 - Prob. 1STCh. 4 - Prob. 2STCh. 4 - Prob. 3STCh. 4 - Prob. 4STCh. 4 - Prob. 5STCh. 4 - Prob. 6STCh. 4 - Prob. 7STCh. 4 - Prob. 8STCh. 4 - Prob. 9STCh. 4 - Prob. 10STCh. 4 - Prob. 11STCh. 4 - Prob. 12STCh. 4 - Prob. 13STCh. 4 - Prob. 14STCh. 4 - Prob. 15STCh. 4 - Prob. 16STCh. 4 - Prob. 17STCh. 4 - Prob. 18ST
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER
Text book image
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
The Bohr Model of the atom and Atomic Emission Spectra: Atomic Structure tutorial | Crash Chemistry; Author: Crash Chemistry Academy;https://www.youtube.com/watch?v=apuWi_Fbtys;License: Standard YouTube License, CC-BY