Chemistry: Structure and Properties Custom Edition for Rutgers University General Chemistry
15th Edition
ISBN: 9781269935678
Author: Nivaldo J. Tro
Publisher: Pearson Education
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Chapter 4, Problem 13SAQ
Interpretation Introduction
Interpretation:
To identify the element which will have the given ionization energies.
Concept introduction:
The energy which is needed to remove an electron or atom from it’s the natural atom or element is known as ionization energy. As we go from left to right across the periodic table the ionization energy will increase, and it will get decreases when we go from right to left vice versa. And also, it will increase when you go up in the periodic table and it will get decrease when you go down the periodic table.
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Consider the following set of successive ionization energies:
IE1=578kJ/mol
IE2=1,820kJ/mol
IE3=2,750kJ/mol
IE4=11,600kJ/mol
To which third-period element do these ionization values belong?
Consider this set of successive ionization energies:IE1 = 578 kJ/mol IE2 = 1820 kJ/molIE3 = 2750 kJ/mol IE4 = 11,600 kJ/molTo which third-period element do these ionization valuesbelong?
Consider this set of ionization energies.
IE, = 578 kJ/mol
IE, = 1820 kJ/mol
IE, = 2750 kJ/mol
IE, = 11,600 kJ/mol
To which third-period element do these ionization values belong?
Chapter 4 Solutions
Chemistry: Structure and Properties Custom Edition for Rutgers University General Chemistry
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