Explanation Introduction: Archimedes’ principle: The buoyant force acting on a substance in a resting fluid is equal to the weight of the fluid that is displaced by substance. F b = weight of displaced fluid. Formula used: Gauge pressure in the liquid: p = D w × h Where, D w is the weight density of liquid. Calculation: Prove of the Archimedes’ principle: Assume the box dimensions are l, w & h. The downward force on the top of the box is: F t o p = p t o p × A t o p Here, P t ° p is the pressure at the top of the box At the bottom of the box, the pressure is higher because it is deeper in fluid Specifically, the pressure p b o t t o m is: p b o t t o m = p t o p + ( D w × h ) Therefore the upward force on the bottom is: F b o t t o m = p b o t t o m × l × w F b o t t o m = [ p t o p + ( D w </

8th Edition

ISBN: 9781337515863

Author: Ostdiek

Publisher: Cengage

See similar textbooks

Concept explainers

Fluid Pressure

The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.

Gauge Pressure

Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem …

Videos

Question

Chapter 4, Problem 13C

To determine

To prove:

Archimedes’’ principle with help of figure 4.36.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 4, Problem 12C

Chapter 4, Problem 14C

Students have asked these similar questions

A ball of mass m = 1.95 kg is released from rest at a height h = 57.0 cm above a light vertical spring of force constant k as in Figure [a] shown below. The ball strikes the top of the spring and compresses it a distance d = 7.80 cm as in Figure [b] shown below. Neglecting any energy losses during the collision, find the following. т h m a d T b (a) Find the speed of the ball just as it touches the spring. m/s (b) Find the force constant of the spring. kN/m

Truck suspensions often have "helper springs" that engage at high loads. One such arrangement is a leaf spring with a helper coil spring mounted on the axle, as shown in the figure below. When the main leaf spring is compressed by distance yo, the helper spring engages and then helps to support any additional load. Suppose the leaf spring constant is 5.05 × 105 N/m, the helper spring constant is 3.50 x 105 N/m, and y = 0.500 m. Truck body yo Main leaf spring -"Helper" spring Axle (a) What is the compression of the leaf spring for a load of 6.00 × 105 N? m (b) How much work is done in compressing the springs? ]

A block of mass m₁ = 10.0 kg is connected to a block of mass m₂ 34.0 kg by a massless string that passes over a light, frictionless pulley. The 34.0-kg block is connected to a spring that has negligible mass and a force constant of k = 200 N/m as shown in the figure below. The spring is unstretched when the system is as shown in the figure, and the incline is frictionless. The 10.0-kg block is pulled a distance h = 22.0 cm down the incline of angle = 40.0° and released from rest. Find the speed of each block when the spring is again unstretched. Vm1 × 1.32 Vm2 = 1.32 × m/s m/s

Chapter 4 Solutions

Inquiry into Physics

Ch. 4 - Prob. 1LA Ch. 4 - Fill in the blanks of this little story with the...Ch. 4 - Prob. 1LTA Ch. 4 - Prob. 2LTA Ch. 4 - Prob. 1PIP Ch. 4 - Prob. 2PIP Ch. 4 - 1. In Section 4.1 in the description of matter,...Ch. 4 - Review Section 4.3 carefully. Based on your...Ch. 4 - (Indicates a review question, which means it...Ch. 4 - (Indicates a review question, which means it...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

To prove: Archimedes’’ principle with help of figure 4.36.

Solution Summary: The author illustrates Archimedes' principle with the help of figure 4.36. The buoyant force acting on a substance is equal to the weight of the fluid displaced by substance.