The categorization of the given substance as an acid or a base and as an electrolyte or non- electrolyte. Concept introduction: The pH -scale is used to identify the acidic or basic nature of given substance. Compound that accepts a proton is a base. Compound that donates a proton is an acid. An electrolyte is the substance which dissolves in water to produce ions.
The categorization of the given substance as an acid or a base and as an electrolyte or non- electrolyte. Concept introduction: The pH -scale is used to identify the acidic or basic nature of given substance. Compound that accepts a proton is a base. Compound that donates a proton is an acid. An electrolyte is the substance which dissolves in water to produce ions.
Interpretation: The categorization of the given substance as an acid or a base and as an electrolyte or non- electrolyte.
Concept introduction: The pH -scale is used to identify the acidic or basic nature of given substance. Compound that accepts a proton is a base. Compound that donates a proton is an acid. An electrolyte is the substance which dissolves in water to produce ions.
(b)
Interpretation Introduction
Interpretation: The initial concentration of Ritalin in the human’s bloodstream.
Concept introduction: The number of moles is defined as the ratio of given mass in grams to the molar mass. Mol=MassofthegivencompoundMolarmassofthecompound
Molarity (M) is the ratio of number of moles of solute to the volume of the solution in liters.
M=NumberofmoleofRitalinVolumeofthesolution
(c)
Interpretation Introduction
Interpretation: The concentration of the given compound after six hour in the bloodstream.
Concept introduction: The half life of the given compound is calculated by the formula: t12=0.693k
Form above formula we can calculate the value of decay constant (k). After that following formula is used for find the concentration: t=2.303klogInitialconcentrationFinalconcentrationFinalconcentration=ekt2.303Initialconcentration
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…