Bio 121 Campbell Biology Truman College
17th Edition
ISBN: 9781323670637
Author: Urry, Cain
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 39.4, Problem 2CC
Summary Introduction
To explain: The edge effect a common horticulture problem.
Concept introduction:
Light is the vital factor for plants which initiates the growth and development. Plant requires light of good intensity and also for a quality period of time. The growth of plants depends directly on the intensity of light, duration and its wavelength.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
help
Can you please help me answer these questions?
Skryf n kortkuns van die Egyptians pyramids vertel ñ story. Maximum 500 woorde
Chapter 39 Solutions
Bio 121 Campbell Biology Truman College
Ch. 39.1 - What are the morphological differences between...Ch. 39.1 - Cycloheximide is a drug that inhibits protein...Ch. 39.1 - Prob. 3CCCh. 39.2 - Prob. 1CCCh. 39.2 - WHAT IF? If a plant has the double mutation err...Ch. 39.2 - MAKE CONNECTIONS What type of feedback process is...Ch. 39.3 - If an enzyme in field-grown soybean leaves is most...Ch. 39.3 - WHAT IF? If a plant flowers in a controlled...Ch. 39.3 - MAKE CONNECTIONS Plants detect the quality of...Ch. 39.4 - Prob. 1CC
Ch. 39.4 - Prob. 2CCCh. 39.4 - Prob. 3CCCh. 39.5 - What are some drawbacks of spraying fields with...Ch. 39.5 - Chewing insects mechanically damage plants and...Ch. 39.5 - Many fungal pathogens get food by causing plant...Ch. 39.5 - WHAT IF? Suppose a scientist finds that a...Ch. 39 - What are two common ways by which signal...Ch. 39 - Is there any truth to the old adage, "One bad...Ch. 39 - Why did plant physiologists propose the existence...Ch. 39 - Plants that have acclimated to drought stress are...Ch. 39 - Prob. 39.5CRCh. 39 - Prob. 1TYUCh. 39 - Prob. 2TYUCh. 39 - Prob. 3TYUCh. 39 - How may a plant respond to severe heat stress? (A)...Ch. 39 - Level 2: Application/Analysis 5. The signaling...Ch. 39 - If a long-day plant has a critical night length of...Ch. 39 - Prob. 7TYUCh. 39 - DRAW IT Indicate the response to each condition by...Ch. 39 - Level 3: Synthesis/Evaluation 9. EVOLUTION...Ch. 39 - SCIENTIFIC INQUIRY A plant biologist observed a...Ch. 39 - SCIENCE. TECHNOLOGY, AND SOCIETY Describe how our...Ch. 39 - Prob. 12TYUCh. 39 - Prob. 13TYU
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- 1.)What cross will result in half homozygous dominant offspring and half heterozygous offspring? 2.) What cross will result in all heterozygous offspring?arrow_forward1.Steroids like testosterone and estrogen are nonpolar and large (~18 carbons). Steroids diffuse through membranes without transporters. Compare and contrast the remaining substances and circle the three substances that can diffuse through a membrane the fastest, without a transporter. Put a square around the other substance that can also diffuse through a membrane (1000x slower but also without a transporter). Molecule Steroid H+ CO₂ Glucose (C6H12O6) H₂O Na+ N₂ Size (Small/Big) Big Nonpolar/Polar/ Nonpolar lonizedarrow_forwardwhat are the answer from the bookarrow_forward
- what is lung cancer why plants removes liquid water intead water vapoursarrow_forward*Example 2: Tracing the path of an autosomal dominant trait Trait: Neurofibromatosis Forms of the trait: The dominant form is neurofibromatosis, caused by the production of an abnormal form of the protein neurofibromin. Affected individuals show spots of abnormal skin pigmentation and non-cancerous tumors that can interfere with the nervous system and cause blindness. Some tumors can convert to a cancerous form. i The recessive form is a normal protein - in other words, no neurofibromatosis.moovi A typical pedigree for a family that carries neurofibromatosis is shown below. Note that carriers are not indicated with half-colored shapes in this chart. Use the letter "N" to indicate the dominant neurofibromatosis allele, and the letter "n" for the normal allele. Nn nn nn 2 nn Nn A 3 N-arrow_forwardI want to be a super nutrition guy what u guys like recommend mearrow_forward
- Please finish the chart at the bottom. Some of the answers have been filled in.arrow_forward9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. 18 carbons fatty acids 12 carbons 9 glycerol A. Glycerol is broken down to glyceraldehyde 3-phosphate, a glycolysis intermediate via the following pathway shown in the figure below. Notice this process costs one ATP but generates one FADH2. Continue generating ATP with glyceraldehyde-3-phosphate using the standard pathway and aerobic respiration. glycerol glycerol-3- phosphate…arrow_forwardNormal dive (for diving humans) normal breathing dive normal breathing Oz level CO2 level urgent need to breathe Oz blackout zone high CO2 triggers breathing 6. This diagram shows rates of oxygen depletion and carbon dioxide accumulation in the blood in relation to the levels needed to maintain consciousness and trigger the urgent need to breathe in diving humans. How might the location and slope of the O₂ line differ for diving marine mammals such as whales and dolphins? • How might the location and slope of the CO₂ line differ for diving marine mammals such as whales and dolphins? • • Draw in predicted lines for O2 and CO2, based on your reasoning above. How might the location of the Urgent Need to Breathe line and the O2 Blackout Zone line differ for diving marine mammals? What physiological mechanisms account for each of these differences, resulting in the ability of marine mammals to stay submerged for long periods of time?arrow_forward
- foraging/diet type teeth tongue stomach intestines cecum Insectivory numerous, spiky, incisors procumbentExample: moleExample: shrew -- simple short mostly lacking Myrmecophagy absent or reduced in numbers, peg-likeExample: tamandua anteater extremely long simple, often roughened short small or lacking Terrestrial carnivory sharp incisors; long, conical canines; often carnassial cheek teeth; may have crushing molarsExample: dog -- simple short small Aquatic carnivory homodont, spiky, numerousExample: common dolphin -- simple or multichambered (cetaceans only) variable small or absent Sanguinivory very sharp upper incisors; reduced cheek teethExample: vampire bat grooved tubular, highly extensible long small or lacking Herbivory (except nectivores) incisors robust or absent; canines reduced or absent; diastema; cheek teeth enlarged with complex occlusal surfacesExample: beaver -- simple (hindgut fermenters) or multichambered (ruminants) long large Filter feeding none…arrow_forward3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 པར『ན་ cm 30 Species B 4/3, 1/1, 2/2, 4/4 cm 10 Species C 0/4, 0/0,3/3, 3/3 020arrow_forward3. Shown below is the dental formula and digestive tract anatomy of three mammalian species (A, B, and C). What kind of diet would you expect each species to have? Support your answers with what you can infer from the dental formula and what you can see in the diagram. Broadly speaking, what accounts for the differences? Species A 3/3, 1/1, 4/4, 3/3 cm 30 Species B 0/4, 0/0, 3/3, 3/3 cm 10 Species C 4/3, 1/1, 2/2, 4/4 E 0 cm 20 AILarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Biology: The Dynamic Science (MindTap Course List)
Biology
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Cengage Learning