Explanation Given Info: The speed of light is 3.0 × 10 8 m / s and the plank constant is 6.63 × 10 − 34 J ⋅ s . Write the formula to calculate the energy of the hydrogen atom. E n = − 13.6 eV n 2 Here, E n is the energy of the hydrogen atom at nth energy level n is the energy level Substitute n = 1 in the above equation to calculate energy at ground level E 1 = − 13.6 eV 1 2 E = − 13.6 eV (1) Substitute n = 3 in the energy equation to calculate energy at n = 3 . E 3 = − 13.6 eV 3 2 (2) Subtract (1) from (2) to calculate the energy change for the atom. Δ E = E 3 − E 1 Here, Δ E is the energy change for the hydrogen atom Substitute − 13.6 eV for E 1 and − 13.6 eV 3 2 for E 3 in the above equation to calculate Δ E . Δ E = − 13.6 eV ( 1 ( 3 ) 2 − 1 ) = − 13.6 eV ( 1 9 − 1 ) = 12 .09 eV Write the formula to calculate the wavelength of the photon. λ = h c Δ E Here, λ is the wavelength of the photon h is the plank constant c is the speed of light Substitute 4

University Physics with Modern Physics (14th Edition)

14th Edition

ISBN: 9780321973610

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Chapter 39, Problem 39.20E

To determine

The wavelength and frequency of the photon.

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Chapter 39, Problem 39.19E

Chapter 39, Problem 39.21E

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Chapter 39 Solutions

University Physics with Modern Physics (14th Edition)

Ch. 39.2 - Prob. 39.2TYU Ch. 39.3 - Prob. 39.3TYU Ch. 39.4 - Prob. 39.4TYU Ch. 39.5 - Prob. 39.5TYU Ch. 39.6 - Prob. 39.6TYU Ch. 39 - Prob. 39.1DQ Ch. 39 - Prob. 39.2DQ Ch. 39 - Prob. 39.3DQ Ch. 39 - When an electron beam goes through a very small...Ch. 39 - Prob. 39.5DQ

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