Explanation Given The curve with equation x x + 1 + y y + 1 = 1 and the point ( 1 , 1 ) . Formula used: The slope of a tangent line to curve y = f ( x ) at a point ( a , b ) is given by d y d x | ( a , b ) . Point-slope form of the line: The equation of a line with slope m passing through the point ( x 1 , y 1 ) is given by y − y 1 = m ( x − x 1 ) . Calculation: Differentiate the given equation to find the derivative d y d x . d d x ( x x + 1 + y y + 1 ) = d d x ( 1 ) d d x ( x x + 1 ) + d d x ( y y + 1 ) = 0 ( x + 1 ) ⋅ 1 − x ⋅ ( 1 + 0 ) ( x + 1 ) 2 + ( y + 1 ) ⋅ d y d x − y ⋅ ( d y d x + 0 ) ( y + 1 ) 2 = 0 x + 1 − x ( x + 1 ) 2 + y d y d x + d y

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Question

Chapter 3.8, Problem 36E

To determine

The equation of the tangent line to the curve xx+1+yy+1=1 at the point (1, 1) .

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Chapter 3.8, Problem 35E

Chapter 3.8, Problem 37E

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Chapter 3 Solutions

Calculus - Standalone book

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The equation of the tangent line to the curve x x + 1 + y y + 1 = 1 at the point ( 1 , 1 ) .

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The equation of the tangent line to the curve xx+1+yy+1=1 at the point (1, 1) .

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