Explanation Given: Consider the following graph: Calculation: Consider the given graph. Here, from the graph, we notice that the graph is increasing for 1 < x < 2.5 and x > 3.5 . Thus, the derivative is positive for 1 < x < 2

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Concept explainers

Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:

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Question

Chapter 3.1, Problem

To determine

We need to determine the intervals along the x-axis on which the derivative in the given graph is positive.

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Chapter 3 Solutions

Calculus - Standalone book

Ch. 3.1 - Prob. 1PQ Ch. 3.1 - Prob. 2PQ Ch. 3.1 - Prob. 3PQ Ch. 3.1 - Prob. 4PQ Ch. 3.1 - Prob. 5PQ Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E

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We need to determine the intervals along the x -axis on which the derivative in the given graph is positive.

Solution Summary: The author explains that the derivative in the given graph is positive for 1x2.5 and x>3.5 .

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We need to determine the intervals along the x-axis on which the derivative in the given graph is positive.

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Chapter 3 Solutions